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2 years ago

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Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.15 m/s . Her husband Bruce suddenly reali

zes that she left in such a hurry that she forgot her lunch of bagels, so he runs to the window of their apartment, which is a height 44.4 m above the street level and directly above the sidewalk, to throw them to her. Bruce throws them horizontally at a time 8.00 s after Henrietta has passed below the window, and she catches them on the run. You can ignore air resistance.
Required:
a. With what initial speed must Bruce throw the bagels so Henrietta can catch them just before they hit the ground?
b. Where is Henrietta when she catches the bagels?

1 answer:

aleksandr82 [10.1K]2 years ago

5 0

Answer:

a 15.22 m/s

b 45.65 m

Explanation:

Using the same formula,

x = vt, where

x is now 45.65, and

t is 3 s, then

45.65 = 3v

v = 45.65/3

v = 15.22 m/s

See the attachment for the part b. We used the distance gotten in part B, to find question A

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