Question

A gannet is a seabird that fishes by diving from a great height

Answer 1

For constant acceleration along a given direction, we can relate acceleration, velocity and position with the following equation that doesn't involve time:
$v^{2}= v_{0}^{2}+2a(x- x_{0})$
In this equation x is the final position, which we take to be 0.  Also the initial velocity Vo is zero.  Thus the equation simplifies to 
$v^{2}= 2a(- x_{0})$
Putting in v=32m/s, a=-9.81m/s^2 gives
$32^{2}= 2(-9.81)(- x_{0})$
$\frac{32^{2}}{2*9.81}= x_{0}=52.19m$