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Likurg_2 [28]
2 years ago
15

Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The mass o

f Mars is 6.4multiply1023 kg and its radius is 3.4multiply106 m.)
Physics
1 answer:
insens350 [35]2 years ago
5 0

Answer:

295.42 N

Explanation:

From Newton's law of universal gravitation.

F = Gmm'/r².................. Equation 1

Where F = Gravitational force, G = Universal constant, m = mass of the human, m' = mass of mass, r = radius of mass.

Given: m = 80 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m.

Constant: G = 6.67×10⁻¹¹ Nm²/Kg²

Substitute into equation 1

F =  6.67×10⁻¹¹(80)(6.4×10²³ )/( 3.4×10⁶)²

F = 3415.04×10¹²/(11.56×10¹²)

F = 3415.04/11.56

F = 295.42 N

Hence the gravitational force =  295.42 N

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Sally finds herself stranded on a frozen pond so slippery that she can't stand up or walk on it. To save herself, she throws one
8_murik_8 [283]

Answer:

a) 2.5 m/s. (In the opposite direction to the direction in which she threw the boot).

b) The centre of mass is still at the starting point for both bodies.

c) It'll take Sally 12 s to reach the shore which is 30 m from her starting point.

Explanation:

Linear momentum is conserved.

(mass of boot) × (velocity of boot) + (mass of sally) × (velocity of Sally) = 0

5×30 + 60 × v = 0

v = (-150/60) = -2.5 m/s. (Minus inicates that motion is in the opposite direction to the direction in which she threw the boot).

b) At time t = 10 s,

Sally has travelled 25 m and the boot has travelled 300 m.

Taking the starting point for both bodies as the origin, and Sally's direction as the positive direction.

Centre of mass = [(60)(25) + (5)(-300)]/(60+5)

= 0 m.

The centre of mass is still at the starting point for both bodies.

c) The shore is 30 m away.

Speed = (Distance)/(time)

Time = (Distance)/(speed) = (30/2.5)

Time = 12 s

Hope this Helps!!!

7 0
2 years ago
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A student throws a 5.0 newton ball straight up. What is the net force on the ball at its maximum height
Alex787 [66]
Iodine is the answer to your question buddy 
4 0
2 years ago
What do nuclear scientists call a stick of uranium?
nikitadnepr [17]
They call it "rod" or "fission rod". This is because the uranium is the element used for the nuclear fission, where the uranium nuclei disintegrate producing lighter nuclei and energy.
6 0
2 years ago
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A long cylindrical rod of diameter 200 mm with thermal conductivity of 0.5 W/m⋅K experiences uniform volumetric heat generation
LuckyWell [14K]

Answer:

a, 71.8° C, 51° C

b, 191.8° C

Explanation:

Given that

D(i) = 200 mm

D(o) = 400 mm

q' = 24000 W/m³

k(r) = 0.5 W/m.K

k(s) = 4 W/m.K

k(h) = 25 W/m².K

The expression for heat generation is given by

q = πr²Lq'

q = π . 0.1² . L . 24000

q = 754L W/m

Thermal conduction resistance, R(cond) = 0.0276/L

Thermal conduction resistance, R(conv) = 0.0318/L

Using energy balance equation,

Energy going in = Energy coming out

Which is = q, which is 754L

From the attachment, we deduce that the temperature between the rod and the sleeve is 71.8° C

At the same time, we find out that the temperature on the outer surface is 51° C

Also, from the second attachment, the temperature at the center of the rod was calculated to be, 191.8° C

6 0
2 years ago
A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest
IRINA_888 [86]

Answer:Average speed is greater than average velocity.

Explanation  :

Given

student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position

Let x be the length of track and the whole process takes t time

For average speed =\frac{distance\ traveled}{time\ taken}

Average speed=\frac{2x}{t}

For average velocity =\frac{Displacement}{time\ taken}

Since displacement is zero as she returns to its initial position.

Average velocity=0

Therefore Average speed is greater than average velocity.

5 0
2 years ago
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