Answer: 7022.2kg/m³, yes, I was cheated
Explanation:
Density of an object is defined as the ratio of the mass of the object to its volume. Mathematically;
Density = Mass/Volume
Note that the unit of both mass and volume must be standard unit.
Given mass = 0.0158kg
Dimension of the metal = 5mm×15mm×30mm
Note that 1mm = 0.001m
The volume of the metal will be
0.005×0.015×0.03
= 0.00000225m³
Density = 0.0158/0.00000225
Average density of the metal = 7022.2kg/m³
Since the standard density of Gold is 19,320kg/m³ and is higher than the density prescribed for me, it shows the I was cheated.
Gravity changes as the altitude change.<span> The gravitational force is proportional to 1/R2, where R is the distance from the center of the Earth the radius of earth where gravity is 9.8 m/s^2 is 6400 km this will serve as the zero mark.
g1/(g2) = R2^2/(R1)^2
so we set the constant values to R1 and the unknown distance as x
(9.8)/(8.80) = (6400-x)2/(6400)^2
solving for x we will get
x = 345.85 km above the earths surface
</span>
<span>Hope my answer would be a great help for you.
If </span>you have more questions feel free to ask here at Brainly.
<span> </span>
Answer:
The partial pressure of H2 is 0.375 atm
The partial pressure of Ne is also 0.375 atm
Explanation:
Mass of H2 = 1 g
Mass of Ne = 1 g
Mass of Ar = 1 g
Mass of Kr = 1 g
Total mass of gas mixture = 1 + 1 + 1 + 1 = 4 g
Pressure of sealed container = 1.5 atm
Partial pressure of H2 = (mass of H2/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm
Partial pressure of Ne = (mass of Ne/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm
Answer:
a) 36 m
b) 64 m
Explanation:
Given:
v₀ = 0 m/2
v = 12 m/s
t = 6 s
Find: Δx
Δx = ½ (v + v₀) t
Δx = ½ (12 m/s + 0 m/s) (6 s)
Δx = 36 m
The track is 100 m, so the sprinter still has to run another 64 m.
Answer:
Force plane exert on pilot = 4270 N
Explanation:
first convert radius and speed to ms
using formula from force we know that
mass = weight/ gravity = 700 N/ 9.8N/kg= 71.4 kg
Fc= N-mg
N= Fc+ mg As Fc = mv²/R
N= mv²/R + mg
taking m common
N= m( v²/R +g)
= 71.4( (200)²/ 800 + 9.8 )
Force = 4270 N