A student throws a 5.0 newton ball straight up. What is the net force on the ball at its maximum height
1 answer:
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Answer:
Part A : E = ε₀ Q₁/R₁² Volt/meter
Part B : V = ε₀ Q₁/R₁ Volt
Explanation:
Given that,
Charge distributed on the sphere is Q₁
The radius of sphere is R
₁
The electric potential at infinity is 0
<em>Part A</em>
The space around a charge in which its influence is felt is known in the electric field. The strength at any point inside the electric field is defined by the force experienced by a unit positive charge placed at that point.
If a unit positive charge is placed at the surface it experiences a force according to the Coulomb law is given by
F = ε₀ Q₁/R₁²
Then the electric field at that point is
E = F/1
E = ε₀ Q₁/R₁² Volt/meter
Part B
The electric potential at a point is defined as the amount of work done in moving a unit positive charge from infinity to that point against electric forces.
Thus, the electric potential at the surface of the sphere of radius R₁ and charge distribution Q₁ is given by the relation
V = ε₀ Q₁/R₁ Volt
<h2>The hiker will go up to 850 m on the hill</h2>
Explanation:
The total energy gained by the hiker = 140 x 4186 J
This energy is consumed in the potential energy acquired , while climbing up the hill.
The potential energy P.E = mass of hiker x acceleration due to gravity x height
Thus
140 x 4186 = 69 x 10 x h
or h = = 850 m
If the 20% of the total energy is used
the height h₀ = = 170 m
Answer:
The radius is decreasing at 4 mm/s
Explanation:
The volume of a sphere is:
So, when the volume is 972π mm^3 the radius r is:
r = 9mm
Now, the change rate is given by the derivative:
Where: dV/dt = -324π mm^2/s
r = 9mm
Solving for dr/dt:
dr/dt = -4mm/s
Answer:
0.01154 A
Explanation:
We have given the energy in the magnetic field
Value of inductance L =0.060 H
Energy stored in magnetic field is given by
So the current flowing through rectangular toroid will be 0.01154 A