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2 years ago

How far could a rabbit run if it ran 36km/h for 5.0min?

Physics

2 answers:

krok68 [10]2 years ago

5 0

Distance = (speed) x (time)

The question GIVES us both the speed and the time. Sadly, though, in order to work with them, we need them to both have the same units, but the information we're given has two different units for time:

The speed is in (km per HOUR), but the time is in MINUTES. We'll have to change one or the other before we can multiply them.

Well, 5.0 minutes is (5/60) = 1/12 of an hour. We can use that.

Distance = (36 km/hr) x (1/12 hour)

Distance = (36/12) (km-hr/hr)

Distance = 3 km .

= = = = = = = = = =

There's a slightly different way to handle it. If the problem was more complicated, this way would actually turn out to be a better way, and you'd have LESS chance of making a mistake if you did it this way:

Distance = (36 km/hr) x (5.0 min)

Distance = (36 x 5) km - min / hr

Distance = 180 km · min / hr

This is a correct answer, but the unit is awkward. We can change the unit at THIS point in our calculation. All we have to do is multiply the answer by ' 1 ' !

We'll find a fraction that has the same number on top or bottom, but in different units, and we'll multiply our answer by this fraction. It won't CHANGE our answer because we're only multiplying it by ' 1 '; but If we're clever about how we build the fraction, it can solve the problem of the units for us.

The fraction to use is . . . (1 hour / 60 minutes) .

The top and the bottom are the same quantity, so the value of the fraction is ' 1 ', and we can multiply our answer by it without changing the answer. But watch what it does to our units:

Distance = (180 km · min / hr) · (1 hr / 60 min)

Distance = (180 · 1 / 60) (km · min · hr / hr · min)

(Do some canceling, and you get ...)

Distance = 3 km

Thank you. Thank you very much. Thank you. I'll be here until Thursday. don't forget to tip your waiter.

Korolek [52]2 years ago

4 0

3 kilometers, it is just 5/60 or 1/12 multiplied by 36.

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Lamar writes several equations trying to better understand potential energy. H = d with an arrow to the equation W = F d and P E

Debora [2.8K]

Answer:

The gravitational potential energy equals the work needed to lift the object.

Explanation:

here we know that

$H = \vec d$

work done is given as

$W = \vec F . \vec d$

Potential energy is given as

$PE_g = mgh$

force due to gravity is given as

$\vec F_g = mg$

now here if we plug in the value of distance and force in the formula of work done then we will have

$W = (mg)(h)$

so here we got

$W = PE_g$

so we can concluded that

The gravitational potential energy equals the work needed to lift the object.

3 0

1 year ago

Read 2 more answers

Suppose you are drinking root beer from a conical paper cup. The cup has a diameter of 10 centimeters and a depth of 13 centimet

sveta [45]

Answer:

The level of the root beer is dropping at a rate of 0.08603 cm/s.

Explanation:

The volume of the cone is :

$V=\frac {1}{3}\times \pi\times r^2\times h$

Where, V is the volume of the cone

r is the radius of the cone

h is the height of the cone

The ratio of the radius and the height remains constant in overall the cone.

Thus, given that, r = d / 2 = 10 / 2 cm = 5 cm

h = 13 cm

r / h = 5 / 13

r = {5 / 13} h

$V=\frac {1}{3}\times \frac {22}{7}\times ({{{\frac {5}{13}\times h}}})^2\times h$

$V=\frac {550}{3549}\times h^3$

Also differentiating the expression of volume w.r.t. time as:

$\frac {dV}{dt}=\frac {550}{3549}\times 3\times h^2\times \frac {dh}{dt}$

Given: $\frac {dV}{dt}$ = -4 cm³/sec (negative sign to show leaving)

h = 10 cm

So,

$-4=\frac{550}{3549}\times 3\times {10}^2\times \frac {dh}{dt}$

$\frac{55000}{1183}\times \frac {dh}{dt}=-4$

$\frac {dh}{dt}=-0.08603\ cm/s$

The level of the root beer is dropping at a rate of 0.08603 cm/s.

3 0

1 year ago

Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh

PIT_PIT [208]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value is $F_j = 550\ N$

Explanation:

From the question we are told that

The length of the stretcher is $d = 2.0 \ m$

The weight of the stretcher is $W = 100 \ N$

The weight for Wayne is $W_w = 800 \ N$

The distance of center of gravity for Wayne from Chris is $c_w = 75 cm = 0.75 \ m$

Generally taking moment about the first end where Chris is

$F_j * d$ => upward moment

Here $F_j$ is the force applied by Jamie

Generally taking moment about the second end where Jamie is

$W * ( \frac{d}{2} ) + W_w * (d - c_w)$ => downward moment

Generally at equilibrium , the upward moment is equal to the downward moment

$F_j * d = W * ( \frac{d}{2} ) + W_w * (d - c_w)$

=> $F_j * 2 = 100 * ( \frac{ 2}{2} ) + 800 * (2 - 0.75)$

=> $F_j = 550\ N$

3 0

1 year ago

A transmission channel is made up of three sections. The first section introduces a loss of 16dB, the second an amplification (o

AlekseyPX

Answer:

$P_{out} = 0.100 W = 100 mW$

Explanation:

The attached image shows the system expressed in the question.

We can define an expression for the system.

The equivalent equation for the system would be

$G_{total} = G_{1} + G_{2} + G_{3}\\G_{total} = -16dB+20dB-10 dB = -6 dB$

so, the input signal could be expressed in dB terms

$P_{in} [dB] = 10 log_{10}(P_{in}) \\P_{in} [dB] = 10 log_{10}(0.4)\\P_{in} [dB] = -3.97 dB$ (1)

so the output signal could be expressed as.

$P_{out} = P_{in} + G_{1} + G_{2} + G_{3}\\P_{out} = -3.97 dB - 6dB = -9.97 dB$

The gain should be expressed in dB terms and power in dBm terms so

$P_{out} = -9.97 + 30 = 20.03 dBm$

using the (1) equation to find it in terms of Watts

$P_{out} = 0.100 W = 100 mW$

3 0

2 years ago

To move a suitcase up to the check-in stand at the airport a student pushes with a horizontal force through a distance of 0.95 m

hoa [83]

Answer:

33.68 N

Explanation:

Data

W= 32J

d- 0.95m

F= ?

W=Fd

They are asking for the magnitude which is the force, so you need to solve for force.

F=W/d

= 32J/ 0.95m

= 33.68 N

3 0

1 year ago