Ask question

Ask question

All categories

1 year ago

9

8. The resistance of a bagel toaster is 14 Ω. To prepare a bagel, the toaster is operated for one minute from a 120-V outlet. Ho

w much energy is deliv

2 answers:

IgorC [24]1 year ago

7 0

Answer: The energy delivered to the toaster is 264.490KJ

Explanation:

Here is the complete question:

The resistance of a bagel toaster is 14 ?. To prepare a bagel, the toaster is operated for one minute from a 120-V outlet. How much energy is delivered to the toaster?

Step-by-step explanation:

Please see attachment below

ki77a [65]1 year ago

5 0

Answer:

61714.29 J

Explanation:

Energy: This can be defined as the ability or the capacity to do work. The S.I unit of energy is Joules.

From the question,

Electrical energy is given as

E = V²t/R.................... Equation 1

Where V = Voltage, t = time, R = resistance.

Given: V = 120 V, t = 1 min = 1×60 = 60 s, R = 14 Ω

Substitute into equation 1

E = 120²(60)/14

E = 14400×60/14

E = 61714.29 J

Hence the energy delivered = 61714.29 J

You might be interested in

What's the momentum of a 3.5-kg boulder rolling down hill at 5 m/s

ICE Princess25 [194]

P = mv
p = 3.5 × 5
p = 17.5 kg .m/s

Hope this helps!

6 0

2 years ago

Paintball guns were originally developed to mark trees for logging. A forester aims his gun directly at a knothole in a tree tha

emmasim [6.3K]

Answer:

The distance between knothole and the paint ball is 0.483 m.

Explanation:

Given that,

Height = 4.0 m

Distance = 15 m

Speed = 50 m/s

The angle at which the forester aims his gun are,

$\tan\theta=\dfrac{4}{15}$

$\tan\theta=0.266$

$\cos\theta=\dfrac{15}{\sqrt{15^2+4^2}}$

$\cos\theta=0.966$

Using the equation of motion of the trajectory

The horizontal displacement of the paint ball is

$x=(u\cos\theta)t$

$t=\dfrac{x}{u\cos\theta}$

Using the equation of motion of the trajectory

The vertical displacement of the paint ball is

$y=u\sin\theta(t)-\dfrac{1}{2}gt^2$

$y=u\sin\theta(\dfrac{x}{u\cos\theta})-\dfrac{1}{2}g(\dfrac{x}{u\cos\theta})^2$

$y=x\tan\theta-\dfrac{gx^3}{2u^2(\cos\theta)^2}$

Put the value into the formula

$y=(15\times0.266)-(\dfrac{9.8\times(15)^2}{2\times(50)^2\times(0.966)^2})$

$y=3.517\ m$

We need to calculate the distance between knothole and the paint ball

$d=h-y$

$d=4-3.517$

$d=0.483\ m$

Hence, The distance between knothole and the paint ball is 0.483 m.

8 0

2 years ago

Han and Greedo fire their blasters at each other. The blasts are loud, and the intensity of the sound spreads through the cantin

noname [10]

I will say it is B; the Inverse square law.
Ohms has to do with electricity and the other 2 just have to do with regular physics.

7 0

1 year ago

Read 2 more answers

The total negative charge on the electrons in 1kg of helium (atomic number 2, molar mass 4) is____________.

tekilochka [14]

Answer:

Explanation:

$n = \frac{m}{M}$

$n = \frac{1000}{4}$

= 250 moles.

N = n×6.02× $10^{23}$

= 1.505× $10^{26}$

Total charge = (1.505× $10^{26}$ ) × (1.6× $10^{-19}$ )

= 2.4× $10^{7}$ C.

4 0

1 year ago

Read 2 more answers

The Lamborghini Huracan has an initial acceleration of 0.80g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode al

irina [24]

Answer:

a = 15.1 g

Explanation:

The relation between mass and acceleration is given by :

$m\propto \dfrac{1}{a}$

If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂

So,

$\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}\\\\a_2=\dfrac{a_1m_1}{m_2}\\\\a_2=\dfrac{0.8g\times 1510}{80}\\\\a_2=15.1g$

So, the car's acceleration would be 15.1 g.

6 0

1 year ago