A farsighted girl has a near point at 2.0 m but has forgotten her glasses at home. The girl borrows eyeglasses that have a power
of 2.75 diopters. These are not going to make her able to view normally. With these eyeglasses, what is the new near point of the girl, assuming that she wears them extremely close to her eyes
1 answer:
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Jogger moves in three displacements
d1 = 10 blocks East
d2 = 5 blocks South
d3 = 2 blocks East
now we can say
total displacement towards East direction will be
Total displacement towards South
now to find the net displacement we can use vector addition
<em>so magnitude of net displacement will be equal to 13 blocks</em>
Answer:
Horizontal component:
Vertical component:
Explanation:
To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.
Therefore, for the horizontal component, we have:
For the vertical component, we have:
So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.
Explanation:
It is given that,
Area of square coil,
Side of the square, L = 0.02 m
Number of turns, N = 10000
Uniform magnetic field, B = 1.5 T
Speed, v = 100 m/s
An emf is induced in the coil which is given by :
E = 30000 V
Breakdown voltage of air,
Let d is the gap between the two wires connected to the ends of the coil and still get a spark. So,
Electric field,
d = 0.075 m
Hence, this is the required solution.