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2 years ago

If E1 = 13.0 V and E2 = 5.0 V , calculate the current I2 flowing in emf source E2.

Physics

1 answer:

swat322 years ago

3 0

The solution would be like this for this specific problem:

KCL at Junction a. 
+ I1 + I2 + I3 = 0 (1) 

KVL
+ 13 V - 0.2 R I1 - 0.025 R I1 - 5 V + 0.02 R I2 = 0 (2) 
8 + 0.02 I2 = 0.225 I1 
I1 = 35.6 + 0.0889 I2 (2A)

KVL (bottom loop - CCW direction) 
- 0.02 R I2 + 5 V + 0.5 R I3 = 0 (3) 
0.5 I3 = -5 + 0.02 I2 
I3 = -10 + 0.04 I2 (3A)

Replace 2A and 3A into 1. 

+ I1 + I2 + I3 = 0 
( 35.6 + 0.0889 I2 ) + I2 + ( -10 + 0.04 I2 ) = 0 
1.129 I2 = -25.6 
I2 = -22.6A 

Solve 2A and 3A for other currents. 

I1 = 35.6 + 0.0889 I2 = 35.6 + 0.0889 * -22.6 = 33.5A 
I3 = -10 + 0.04 I2 = -10 + 0.04 * -22.6 = -10.9A

So the answer is letter D.

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