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Anna35 [415]
1 year ago
13

A 25-coil spring with a spring constant of 350 N/m is cut into five equal springs with five coils each. What is the spring const

ant of each of the 5-coil springs
Physics
1 answer:
DanielleElmas [232]1 year ago
7 0
<h2>Answer:</h2>

1750N/m

<h2>Explanation:</h2>

According to Hooke's law, the spring constant (k) of an elastic material is the ratio of the force (F) applied to the material to the extension (x) of the material caused by this force. i.e

k = F / x         --------------(i)

From the question, the elastic material (spring) of 25 coils has a spring constant of 350N/m. This means that for every 350N force applied to the spring, the spring extends by 1m.

Now if the spring is cut into five equal parts each with five coils, imagine they are attached together such that the same force of 350N is applied to still cause a total extension of 1m. Each spring contributes 1/5 of this extension.

Therefore, the extension caused by each spring is 1/5 of 1m = 0.2m

Since the same force of 350N is applied, substitute F = 350N and x =  0.2m into equation (i) as follows;

k = 350 / 0.2

k = 1750N/m

Therefore, the spring constant of each of the 5-coil spring is 1750N/m

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Find the truth table for the circuit shown. Explain the working principle for all the inputs, briefly. Explain why D1 is used in
Ymorist [56]

Answer:

  see below for the truth table

Explanation:

<u>Truth Table</u>

As we will see from the description of operation, any input low causes the output to be high. This is the logic of a NAND gate. The truth table is attached.

<u>Working Principle</u>

Pulling any of A, B, or C low will saturate transistor Q1, depriving Q2 of any base current, cutting it off. Then Q5 is also deprived of base current and is cut off. Meanwhile, the current through R2 supplies base current to Q4, allowing it to pull the output high.

If all of A, B, and C are high (or open), base current is supplied to Q2 through the base-collector junction of Q1. Then Q2 saturates, supplying base current to Q3. Diode D1 ensures that the voltage across Q2 will be insufficient to supply any base current to Q4, so it stays cut off.

6 0
1 year ago
Calculate the energy released in joules when one mole of polonium-214 decays according to the following equation21484 Po --&gt;
GuDViN [60]

Answer:

ΔE = 8.77 × 10¹¹ J

Explanation:

given,

²¹⁴₈₄Po -----> ²¹⁰₈₂Pb + 42 He

Atomic masses: Pb-210 = 209.98284 amu

Po-214 = 213.99519 amu

He-4 = 4.00260 amu

1 kg = 6.022 × 10²⁶ amu;

NA = 6.022 × 10²³ mol⁻¹

c = 2.99792458 × 10⁸ m/s

energy of molecule using equation

ΔE = Δm c²

Δm is mass difference and c is speed of light

Δm = 209.98284 + 4.00260 - 213.99519

Δm = - 0.00975 amu

1 amu = 1.66 x 10⁻²⁷ kg

- 0.00975 amu = - 0.00975 x 1.66 x 10⁻²⁷ Kg

                         = -0.016185 x 10⁻²⁷ Kg

total mass = 6.022 × 10²³ x -0.016185 x 10⁻²⁷

                 = -0.097467 x 10⁻⁴ Kg

ΔE = -(0.097467 x 10⁻⁴) (3 x 10^8)²

ΔE = - 8.77 × 10¹¹

ΔE = 8.77 × 10¹¹ J

8 0
2 years ago
Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

or

r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m

The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
1 year ago
Rachel has an unknown sample of a radioisotope listed in the table. Using a special technique, she is able to measure the mass o
mart [117]
<span>Barium-139 is the correct answer.</span>
3 0
2 years ago
Read 2 more answers
Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two sys
baherus [9]

Answer:

a. Springs oscillate with the same frequency

Explanation:

As they both are in the same height at equilibrium, so

weight of ball must be balanced with spring force, that is

k×x=mg

k= stiffness constant of spring

x=distance stretched

g= acceleration due to gravity

so,  we can write

k/m=g/x

as the g is a constant and they stretched to same distance x so the g/x term becomes constant and

f\propto\sqrt{k/m}

and k/m is same for both the springs so they will oscillate at the same frequency.

hence option a is correct.

3 0
2 years ago
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