Answer:
see below for the truth table
Explanation:
<u>Truth Table</u>
As we will see from the description of operation, any input low causes the output to be high. This is the logic of a NAND gate. The truth table is attached.
<u>Working Principle</u>
Pulling any of A, B, or C low will saturate transistor Q1, depriving Q2 of any base current, cutting it off. Then Q5 is also deprived of base current and is cut off. Meanwhile, the current through R2 supplies base current to Q4, allowing it to pull the output high.
If all of A, B, and C are high (or open), base current is supplied to Q2 through the base-collector junction of Q1. Then Q2 saturates, supplying base current to Q3. Diode D1 ensures that the voltage across Q2 will be insufficient to supply any base current to Q4, so it stays cut off.
Answer:
Power output: W=1426.9MW
Explanation:
The power output of the falls is given mainly by its change in potential energy:
The potential energy for any point can be calculated as:
If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:
If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:
Answer:
0.775
Explanation:
The weight of an object on a planet is equal to the gravitational force exerted by the planet on the object:
where
G is the gravitational constant
M is the mass of the planet
m is the mass of the object
R is the radius of the planet
For planet A, the weight of the object is
For planet B,
We also know that the weight of the object on the two planets is the same, so
So we can write
We also know that the mass of planet A is only sixty percent that of planet B, so
Substituting,
Now we can elimanate G, MB and m from the equation, and we get
So the ratio between the radii of the two planets is
Answer:
0.0984
Explanation:
From the first diagram attached below; a free flow diagram shows the interpretation of this question which will be used to solve this question.
From the diagram, the horizontal component of the force is:
Replacing 42° for θ and 87.0° for
On the other hand, the vertical component is ;
Replacing 42° for θ and 87.0° for
However, resolving the vector, let A be the be the component of the mutually perpendicular directions.
The magnitude of the two components is shown in the second attached diagram below and is now be written as A cos θ and A sin θ
The expression for the frictional force is expressed as follows:
Where;
is said to be the coefficient of the friction
N = the normal force
Similarly the normal reaction (N) = mg - F sin θ
Replacing . The normal reaction can now be:
By balancing the forces, the horizontal component of the force equals to frictional force.
The horizontal component of the force is given as follows:
Making the subject of the formular in the above equation; we have the following:
Replacing the following values: i.e
m = 73 Kh
g = 9.8 m/s²
Then:
Thus, the coefficient of friction is = 0.0984
