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trasher [3.6K]
1 year ago
5

Calculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration

due to gravity. Explicitly show how you follow the steps in the Problem-Solving Strategy for Newton’s laws of motion.
Physics
1 answer:
worty [1.4K]1 year ago
3 0

Answer:

3433.5 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of person = 70 kg

According to the question

a = Acceleration

4g=4\times 9.81\\\Rightarrow a=39.24\ m/s^2

Balancing the forces we have

F-w=ma\\\Rightarrow F=ma+w\\\Rightarrow F=ma+mg\\\Rightarrow F=m(a+g)\\\Rightarrow F=70(39.24+9.81)\\\Rightarrow F=3433.5\ N

The required force is 3433.5 N

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Answer:

The banking angle necessary for the race cars is 34.84°

Explanation:

For normal reaction the expression is:

\\Nsin\theta = \frac{mv^{2} }{R}  =Fc\\tan\theta =\frac{v^{2} }{Rg}  \\\theta =tan^{-1} (\frac{v^{2} }{Rg} )\\\theta =tan^{-1} (\frac{(102*0.447)^{2} }{1000*0.3048*9.8} )=34.84

4 0
1 year ago
An object of mass M is dropped near the surface of Earth such that the gravitational field provides a constant downward force on
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Answer:

The answer is: c. It does not move

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1 year ago
An automobile accelerates from zero to 30 m/s in 6.0 s. The wheels have a diameter of 0.40 m. What is the average angular accele
leva [86]

To solve this problem we will use the concepts related to angular motion equations. Therefore we will have that the angular acceleration will be equivalent to the change in the angular velocity per unit of time.

Later we will use the relationship between linear velocity, radius and angular velocity to find said angular velocity and use it in the mathematical expression of angular acceleration.

The average angular acceleration

\alpha = \frac{\omega_f - \omega_0}{t}

Here

\alpha = Angular acceleration

\omega_{f,i} = Initial and final angular velocity

There is not initial angular velocity,then

\alpha = \frac{\omega_f}{t}

We know that the relation between the tangential velocity with the angular velocity is given by,

v = r\omega

Here,

r = Radius

\omega = Angular velocity,

Rearranging to find the angular velocity

\omega = \frac{v}{r}}

\omega = \frac{30}{0.20} \rightarrow Remember that the radius is half te diameter.

Now replacing this expression at the first equation we have,

\alpha = \frac{30}{0.20*6}

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Therefore teh average angular acceleration of each wheel is 25rad/s^2

3 0
2 years ago
Consider four different oscillating systems, indexed using i = 1 , 2 , 3 , 4 . Each system consists of a block of mass mi moving
Rzqust [24]

Answer:

The order is 2>4>3>1 (TE)

Explanation:

Look up attached file

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2 years ago
Suppose you look out the window of a skyscraper and see someone throw a tomato downward from above your window. your window is a
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Formula for height 
<span> r(t) = a/2 t² + v₀ t + r₀
</span><span> where 
</span><span> a = acceleration = -32 ft/sec² (gravity) 
</span><span> v₀ = initial velocity 
</span><span> r₀ = initial height 
</span><span> r(t) = -16t² + v₀ t + r₀
</span> <span>Tomato passes window (height = 450 ft) after 2 seconds: 
</span><span> r(2) = 450
</span><span> -16(4) + v₀ (2) + r₀ = 450 
</span><span> r₀ = 450 + 64 - 2v₀ 
</span><span> r₀ = 514 - 2v₀ 
</span><span> Tomato hits the ground (height = 0 ft) after 5 seconds: 
</span><span> r(5) = 0 
</span><span> -16(25) + v₀ (5) + r₀ = 0
</span> r<span>₀ = 16(25) - 5v₀ 
</span><span> r₀ = 400 - 5v₀ 
</span><span> 
 r₀ = 514 - 2v₀ and r₀ = 400 - 5v₀
</span> <span>514 - 2v₀ = 400 - 5v₀
</span><span> 5v₀ - 2v₀ = 400 - 514
</span> <span>3v₀ = −114 
</span><span> v₀ = −38 
</span><span> Initial velocity = −38 ft/sec (so tomato was thrown down) 
</span><span> (initial height = 590 ft) </span>
4 0
2 years ago
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