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Gala2k [10]
2 years ago
12

Rank in order, from largest to smallest, the magnitudes of the horizontal forces F1, F2, and F3 acting on the arrows. Some may b

e equal. State your reasoning. Rank in order, from largest to smallest, the magnitudes of the horizontal forces , , and acting on the arrows. Some may be equal. State your reasoning.
a. F3>F1=F2 because the mass of the first arrow is equal to the mass of the second arrow which is less than the mass of the third arrow.
b. F1=F2=F3=0 because there is no change in the horizontal motion of the arrows.
c. F1>F2=F3 because the velocity of the second arrow is equal to the velocity of the third arrow which is less than the velocity of the first arrow.
d. F1=F2=F3>0 because there is no change in the horizontal motion of the arrows.
Physics
1 answer:
gladu [14]2 years ago
6 0

Answer:

b. F1=F2=F3=0 because there is no change in the horizontal motion of the arrows.

Explanation:

The three arrows in the given problem have been shot and it is assumed that air resistance can be neglected. The motions of the arrows are in horizontal direction and as such there is no obvious change in the horizontal motion of the three arrows. Therefore, the three forces are equivalent to one another and each force is equal to zero (i.e. F1=F2=F3=0).

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Shareen performs a skit to model a method of charging. In the skit, a painter shakes her hand and gets paint on her.
Veseljchak [2.6K]

Answer:

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

Explanation:

Conduction phenomenon of charging is the process of charging in which two bodies are made in contact with each other so that charges are transferred due to potential difference of two bodies.

here we know that when hands are shake then it will have paint on it. so here due to hand shake the hands are in contact with charge particles and due to contact the electrons are transferred to the hand.

Now here we need to assume that charge of paint must be opposite that of the charge on the hand because only due to opposite charge attraction the paint must be transferred to the hand

SO here correct answer will be

It models conduction because the painter represents a charged object and the paint represents electrons that are transferred through contact.

5 0
1 year ago
Read 2 more answers
550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c
Over [174]

Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

Work done = 550 J

Volume change = V₂ - V₁ = -0.5V₁

Thus the product of pressure and volume change = work done by gas, thus

P × -0.5V₁ = 500 J

Hence -PV₁ = 1000 J

also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore  P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

Also to compress the gas by a factor of 11 we have

P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11  = 909.091 J of work

7 0
2 years ago
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
erastovalidia [21]
Would presume you are asked to find the volume, since there is no second volume.

By General Gas Law:

P₁V₁/T₁ = P₂V₂/T₂

1.6 * 168 /255 = 1.3*V₂/285

V₂ = 1.6 * 168 * 285 / (1.3*255)

V₂ = 231.095

Final volume ≈ 231 cm³
7 0
2 years ago
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A 20.0 kg rock is sliding on a rough , horizontal surface at8.00 m/s and eventually stops due to friction .The coefficient ofkin
ra1l [238]

Answer: The power is 156 watt

Explanation:

is in the attachment

3 0
2 years ago
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For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
nydimaria [60]

Answer:

The width of slide is 0.092 mm.

Explanation:

Given that,

Wave length = 680 nm

Distance between slit and screen D= 5.4 m

Distance of bright band 2y = 7.9 cm

y =\dfrac{7.9}{2}

y=3.95\ cm

We need to calculate the width of slide

Using formula of width

d=\dfrac{\lambda D}{y}

Where, d = width

D =Distance between slit and screen

y = Distance of bright band

Put the value into the formula

d=\dfrac{680\times10^{-9}\times5.4}{3.95\times10^{-2}}

d=0.092\times10^{-3}\ m

d=0.092\ mm

Hence, The width of slide is 0.092 mm.

4 0
2 years ago
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