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2 years ago

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Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two sys

tems reach equilibrium. Then both springs are compressed and released. Which one oscillates faster? a. Springs oscillate with the same frequency. b. The spring with the heavier ball. c. The spring with the lighter ball. d. It is impossible do determine without additional data.

1 answer:

baherus [9]2 years ago

3 0

Answer:

a. Springs oscillate with the same frequency

Explanation:

As they both are in the same height at equilibrium, so

weight of ball must be balanced with spring force, that is

k×x=mg

k= stiffness constant of spring

x=distance stretched

g= acceleration due to gravity

so, we can write

k/m=g/x

as the g is a constant and they stretched to same distance x so the g/x term becomes constant and

$f\propto\sqrt{k/m}$

and k/m is same for both the springs so they will oscillate at the same frequency.

hence option a is correct.

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Answer:

First Question

$E = 1.065*10^{-12} \ J$

Second Question

The wavelength is for an X-ray

Explanation:

From the question we are told that

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Gnerally the energy (in MeV) of the photon emitted when the proton undergoes a transition is mathematically represented as

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Here h is the Planck's constant with value $h = 6.62607015 * 10^{-34} J \cdot s$

m is the mass of proton with value $m = 1.67 * 10^{-27} \ kg$

So

$E = \frac{( 6.626*10^{-34})^2 }{ 8 * (1.67 *10^{-27}) * (10 *10^{-15})^2 [ 2^2 - 1 ^2 ] }$

=> $E = 1.065*10^{-12} \ J$

Generally the energy of the photon emitted is also mathematically represented as

$E = \frac{h * c }{ \lambda }$

=> $\lambda = \frac{h * c }{E }$

=> $\lambda = \frac{6.62607015 * 10^{-34} * 3.0 *10^{8} }{ 1.065 *10^{-15 } }$

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1 year ago

A 74.9 kg person sits at rest on an icy pond holding a 2.44 kg physics book. he throws the physics book west at 8.25 m/s. what i

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Answer:

The recoil velocity is 0.2687 m/s.

Explanation:

∵ The person is sitting on an icy surface , we can assume that the surface is frictionless.

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If 'i' and 'f' be the initial and final states of this system , then by principle of conservation of momentum(p) -

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∴ $p_{i}$ =0

∴ From the above 2 equations

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We know that ,

Momentum(p)=Mass of the body(m)×velocity of the body(v)

Let $m_{1}$ and $m_{2}$ be the mass of the person and the book respectively and $v_{1}$ and $v_{2}$ be the final velocities of the person and book respectively.

∴ $p_{f}$ = $m_{1}$ $v_{1}$ + $m_{2}$ $v_{2}$ =0

From the question ,

$m_{1}$ = 74.9 kg

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Substituting these values in the above equation we get ,

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2 years ago

Two thin lenses with a focal length of magnitude 12.0cm, the first diverging and the second converging, are located 9.00cm apart

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Answer:

Explanation:

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1 / v = - 1 / 20 -1 / 12

= - .05 - .08333

= - .13333

v = - 1 / .13333

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c )

For second lens

object distance u = - 16.5 cm

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1 / v - 1 / u = 1 / f₂

1 / v + 1 / 16.5 = 1 / 12

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= .08333- .0606

= .02273

v = 1 / .02273

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e )

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1 year ago

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Answer:

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2 years ago