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andriy [413]
2 years ago
12

A car is traveling with speed v0 when it begins to speed up at a rate of Δv every second. After t1 seconds, the car travels with

zero acceleration for t2 seconds. Which of the following is a correct expression for the displacement of the car during this motion?
Physics
1 answer:
Rainbow [258]2 years ago
8 0

Answer:

d = Δv(t2-t1)

Explanation:

Speed is defined as the change of displacement with respect to time. It is expressed as shown;

Speed = change in displacement/change in time

Δv = d/Δt

d = Δv*Δt

d = ΔvΔt

Δt = t2-t1

d = Δv(t2-t1)

Δv is the change in rate of speed

Δt = change in time

The correct expression for the displacement of the car during this motion is d = Δv(t2-t1)

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Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two sys
baherus [9]

Answer:

a. Springs oscillate with the same frequency

Explanation:

As they both are in the same height at equilibrium, so

weight of ball must be balanced with spring force, that is

k×x=mg

k= stiffness constant of spring

x=distance stretched

g= acceleration due to gravity

so,  we can write

k/m=g/x

as the g is a constant and they stretched to same distance x so the g/x term becomes constant and

f\propto\sqrt{k/m}

and k/m is same for both the springs so they will oscillate at the same frequency.

hence option a is correct.

3 0
2 years ago
A woman makes 50% more than her husband. Together they make $2500 each month? How much does the woman earn each month?a) $950b)
Sergeeva-Olga [200]

Answer:b

Explanation:

Given

Woman earn 50% more than her husband

Total sum of their money is =\$ 2500

Suppose man earns \$ P

so women earns P+0.5 P=P(1+0.5)=1.5 P

Sum of their money is

P+1.5 P=2500

P=\$ 1000

Women earns =1.5\times 1000=\$ 1500          

6 0
1 year ago
A car of mass 1100kg moves at 24 m/s. What is the braking force needed to bring the car to a halt in 2.0 seconds? N
LenaWriter [7]

13200N

Explanation:

Given parameters:

Mass = 1100kg

Velocity = 24m/s

time = 2s

unknown:

Braking force = ?

Solution:

The braking force is the force needed to stop the car from moving.

   Force  =  ma = \frac{mv}{t}

  m is the mass of the car

  v is the velocity

  t is the time taken

  Force = \frac{1100 x 24}{2} = 13200N

Learn more:

Force brainly.com/question/4033012

#learnwithBrainly

8 0
2 years ago
Calculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration
worty [1.4K]

Answer:

3433.5 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of person = 70 kg

According to the question

a = Acceleration

4g=4\times 9.81\\\Rightarrow a=39.24\ m/s^2

Balancing the forces we have

F-w=ma\\\Rightarrow F=ma+w\\\Rightarrow F=ma+mg\\\Rightarrow F=m(a+g)\\\Rightarrow F=70(39.24+9.81)\\\Rightarrow F=3433.5\ N

The required force is 3433.5 N

3 0
1 year ago
A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

So;

σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

3 0
2 years ago
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