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inna [77]
2 years ago
7

The leaves of a tree lose water to the atmosphere via the process of transpiration. A particular tree loses water at the rate of

3 x 10^-8 m^3/s; this water is replenished by the upward flow of sap through vessels in the trunk. This tree's trunk contains about 2000 vessels, each 100Mu m in diameter. What is the speed of the sap flowing in the vessels?
Physics
1 answer:
Gnoma [55]2 years ago
7 0

Answer:

The speed of the sap flowing in the vessel is 1.90 mm/s

Explanation:

Given:

The rate of water loss, Q = 3 × 10 ⁻⁸ m³/s

Number of vessels contained, n = 2000

Diameter of the vessel, D = 100 Mu m

thus, the radius of the vessel, r = 50 × 10⁻⁶ m

Now, the rate of flow is given as:

Q = AV    .............(1)

where, A is the area of the cross-section

V is the velocity

Total area, A = n × (πr²)

substituting the values in the equation (1), we get

3 × 10 ⁻⁸ m³/s = [2000 × (π × (50 × 10⁻⁶)²)] × V

or

V = 1.909 × 10⁻³ m/s or 1.90 mm/s

Hence, the speed of the sap flowing in the vessel is 1.90 mm/s

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                           I_s =\frac{ V}{R_T}

                            I_s  = \frac{V_0}{R_1 +R_2} ---(1)

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From the question I_p =10I_s

          =>                 I_p =10I_s = \frac{V_0 }{\frac{R_1R_2}{R_1 +R_2} }  = \frac{V_0 (R_1 +R_2)}{R_1 R_2}---(2)

     Dividing equation 2 with equation 1

       =>                 \frac{10I_s}{I_s} =\frac{\frac{V_0 (R_1 +R_2)}{R_1 R_2}}{\frac{V_0}{R_1 +R_2}}

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                              =  \frac{8 \pm\sqrt{((-8)^2- (4*1*1))} }{2*1}

                               r= \frac{8+ \sqrt{60} }{2}  \ or \  r = \frac{8 - \sqrt{60} }{2}

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