Answer:
d = 380 feet
Explanation:
Height of man = perpendicular= 130 feet
Angle of depression = ∅ = 70 °
distance to bus stop from man = hypotenuse = d = 130 sec∅
As sec ∅ = 1 / cos∅
so d = 130 sec∅ or d = 130 / cos∅
d = 130 / cos(70°)
d = 380 feet
156.8 Joules of energy is in the box's gravitational potential energy store
<u>Explanation</u>:
<em>Given:</em>
Mass of the box Dane is holding = 8 Kilograms
Height at which Dane is holding the box above the ground= 2 metres
<em>To Find:</em>
Gravitational potential energy in the box=?
<em>Solution:</em>
gravitational potential energy is the work done per mass on a object to move that object from one fixed location to to another location against gravity.Its unit is joules or J
Thus Gravitational potential energy is represented as,
where
is the gravitational potential energy
m is the mass
h is the height
g is the gravitational force( 9.8 
)
Now substituting the given values,
The answer is B: energy is transferred, but it can go to the products or the reactants.
You must know the concept of pH of a solution and its relation to the concentration of H+ and OH- ions. pH is a measure of the substance's acidity or basicity. From the definition of Arrhenius, an acid contains an H+ while a base contains a OH- ion. From this definition, we can say that an acidic substance has a higher concentration of H+ ions. Now, I'll introduce here that pH is the value of the negative logarithm of the concentration of H+. In equation,
pH = -log[H+]
The term pOH is therefore also, pOH = -log[OH-]. Therefore, the relationship that connects the two negative logarithms is:
pH + pOH = 14
The pH scale starts from 1 being the most acidic to 14 being the most basic. The neutral pH is 7. Thus, for a pH of 7, the H+ and the OH- concentrations are equal.
pH = 7 = -log[H+][H+] = 1×10⁻⁷ mol/L = [OH-]
Since the concentrations are equal, the ratio is equal to 1.
Answer:
A) 0.33 m/s
Explanation:
The standard form of a transverse wave is given by
y
=
a cos
(
ω
t
−
kx
) , k
= 2
π / λ
Amplitude, a
= 0.002 m
Wavenumber (k)=47.12 and wavelength (
λ
) = 0.133
m
Time period(T)=0.0385 s and angular frequency (
ω
) = 52
π rad/s
Maximum speed of the string is given by aw
Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s
