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yuradex [85]
2 years ago
15

All of these are examples of pseudopsychology EXCEPT:

Physics
2 answers:
bekas [8.4K]2 years ago
6 0

Pick <em>choice-B</em> .

"Pseudo..." means "looks like it but not really".  So we're looking for the choice that's real Psychology.

<em>Psychoanalysis</em> is not an exact science, but it's a waaaay more reliable psychological approach than tarot cards, astrology, or numerology.  Those are nothing but smoke and mirrors.

jeyben [28]2 years ago
4 0

Answer:

psychoanalysis

Explanation:

psychoanalysis a system of psychological theory and therapy which aims to treat mental disorders by investigating the interaction of conscious and unconscious elements in the mind and bringing repressed fears and conflicts into the conscious mind by techniques such as dream interpretation and free association.

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A brick of mass 2 kg is dropped from a rest position 5 m above the ground. what is its velocity at a height of 3 m above the gro
Rina8888 [55]
We can solve the problem by using the law of conservation of energy.

Using the ground as reference point, the mechanical energy of the brick when it is at 5 m from the ground is just potential energy (because the brick is initially at rest, so it doesn't have kinetic energy):
E= U = mgh=(2 kg)((9.81 m/s^2)(5 m)=98.1 J

when the brick is at h'=3 m from the ground, its mechanical energy is now sum of kinetic energy and potential energy:
E= K+U= \frac{1}{2} mv^2 + mgh'

where v is the velocity of the brick. Since E is conserved, it must be equal to the initial energy (98.1 J), so we can solve this equation to find v:
v= \sqrt{ \frac{2(E-mgh')}{m} }=6.3 m/s
8 0
2 years ago
Determine the magnitude and sense (direction) of the current in the 500-latex: \omega ω resistor when i = 30 ma.
VARVARA [1.3K]

Complete Question:

Check the circuit in the file attached to this solution

Answer:

Total current = 0.056 A(From left to right)

Explanation:

Let the current in loop 1 be I₁ and the current in loop 2 be I₂

Applying KVL to loop 1

30 - (I₁ - I₂)500 + I₂R + 15 = 0

45 - 500I₁ - 500I₂ + RI₂ = 0

I₁ = 30mA = 0.03 A

45 - 500(0.03) - 500I₂ + RI₂ = 0

30 -500I₂ + RI₂ = 0...............(1)

Applying kvl to loop 2

-RI₂ - 15 + 10 - 400I₁ = 0

-RI₂ = 5 + 400*0.03

RI₂ = -17 ................(2)

Put equation (2) into (1)

30 -500I₂ -17 = 0

-500I₂ = 13

I₂ = -13/500

I₂ = -0.026 A

The total current in the 500 ohms resistor = I₁ - I₂ = 0.03+0.026

Total current = 0.056 A

The current will flow from left to right

5 0
2 years ago
A point charge with charge q1 is held stationary at the origin. A second point charge with charge q2 moves from the point (x1, 0
Scilla [17]

Answer:

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Explanation:

Position of charge q₁ is (0,0)

Position of charge q₂ is (x₁,0)

So, the electric potential energy between the charges is given by :

U_1=k\dfrac{q_1q_2}{x_1}

Now the position of charge q₂ has been changes from (x₁,0) to (x₂,y₂). Now, electric potential energy between the charges is :

U_2=k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}}

We know form the work energy theorem that, the change in potential energy is equal to the work done. Mathematically, it is given by :

W=-\Delta U

W=-(U_2-U_1)

W=(U_1-U_2)

W=(k\dfrac{q_1q_2}{x_1}-k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}})

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Hence, the work done by the electrostatic force on the moving point charge is kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}}). Hence, this is the required solution.

3 0
2 years ago
What is the maximum negative displacement a dog could have if it started its motion at +3 m?
raketka [301]

Answer:

- 3 meter

Explanation:

A dog has started motion from +3 meter. ...(Given)

∴ maximum positive distance = + 3 meter

Magnitude of distance = 3

Maximum negative distance = (-) (magnitude of distance)

Maximum negative distance = (-) (3)

Maximum negative distance = -3 meter

Hence, maximum negative distance is -3 meter.

7 0
2 years ago
A car drives around a racetrack for 30 seconds. what do you need to know to calculate the average velocity of the car?
boyakko [2]
The time is given, and you want to find the average velocity. To do this, you need to know the distance covered by the driver around the racetrack in that 30 seconds. You divide this by the time, then you will obtain the average velocity in units of, say meters per second.
8 0
2 years ago
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