Answer:
The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds
Explanation:
The given parameters are;
Speed of the car = 120 km/h
Distance from Toronto to Ottawa = 425.5 km
The formula for speed is given as follows;
Speed = Distance/Time
Therefore, to find the time duration it takes from Toronto to Ottawa, we have;
Time duration = Distance from Toronto to Ottawa/(Speed of the car)
The time duration = 425.5/120 = 3.54583 hours = 212.75 min = 12765 seconds
The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.
First, find the needed acceleration needed for the car to stop from its initial velocity given the distance. This is calculated through the equation,
2ad = Vf² - Vi²
where a and d are acceleration and distance, respectively. Vf and Vi are final and initial velocities, respectively. Substituting the known values,
2(a)(35 m) = (0 m/s)² - ((65 km/h) x (1000 m/ 1 km) x (1 hr / 3600 s))²
The value of acceleration is -4.66 m/s².
The force needed to stop the car is the product of the mass and the acceleration. The operations gives us an answer of -4,660 N. We take the positive value, 4,660 N.
You knew that this question is ridiculously easy. So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".
The description is talking about a parallel circuit. The other
kind is a series circuit, and that one has no forks in the road.
Answer:
a) amount of kinetic energy converted to internal energy = 2.5 x 10 raised to power 7 Joule
b) Kinetic energy gained by the earth = 2.1 x 10-16J
c) All the kinetic energy is converted to internal energy and the energy is further converted to thermal energy hence the reason for the hotness at around where the meteorite strikes.
Explanation:
The detailed steps and appropriate application of the law of conservation of momentum is as shown in the attached file.
In the circular motion of the hammer, the centripetal force is given by

where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find: