Ask question

Ask question

All categories

2 years ago

5

Calculate the distance the marble travels during the first 3.0 seconds. [Show all work, including the equation and substitution

with units.]

1 answer:

Alenkinab [10]2 years ago

3 0

D = V0t + 0.5at^2

Where d is the distance

V0 is the initial velocity

A is the acceleration

T is time

From the graph a = 4/3 m/s2

D = 0(3) + 0.5( 4/3 m/s2) ( 3 s)^2

D = 6 m

You might be interested in

the grid in a triode is kept negatively charged to prevent… a. the variations in voltage from getting too large. b. electrons be

Nezavi [6.7K]

D:the electrons from being attracted to the grid instead of the anode

5 0

2 years ago

Read 2 more answers

If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reactio

pentagon [3]

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide $(CO)$ = 28 g/mole

Molar mass of oxygen $(O_2)$ = 32 g/mole

First we have to calculate the moles of carbon monoxide.

$\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=\frac{56g}{28g/mole}=2moles$

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

$2CO+O_2\rightarrow 3CO_2$

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of $O_2$

So, the moles of $O_2$ = 1 mole

Now we have to calculate the mass of oxygen.

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=1mole\times 32g/mole=32g$

Therefore, the mass of oxygen involved in the reaction is, 32 grams.

5 0

2 years ago

The total negative charge on the electrons in 1kg of helium (atomic number 2, molar mass 4) is____________.

tekilochka [14]

Answer:

Explanation:

$n = \frac{m}{M}$

$n = \frac{1000}{4}$

= 250 moles.

N = n×6.02× $10^{23}$

= 1.505× $10^{26}$

Total charge = (1.505× $10^{26}$ ) × (1.6× $10^{-19}$ )

= 2.4× $10^{7}$ C.

4 0

2 years ago

Read 2 more answers

The discovery and characterization of cathode rays was important in the development of the atomic theory because

Viefleur [7K]

Answer:

All matter contained electrons

Explanation:

The discovery and characterization of cathode ray suggested that it was a subatomic particle and cathode ray ( electron) was the first discovered. It immensely became the strong explanatory tool for chemical bond. This can be attributed to the the ease with which electron move from one atom to the other.

3 0

2 years ago

A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d

zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A = $\pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}$

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

$Y=\frac{F\times L}{A\times\Delta L}$

$\Delta L = \frac{F\times L}{A\times Y}$

$\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}$

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

8 0

2 years ago