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andrey2020 [161]
1 year ago
6

A woman makes 50% more than her husband. Together they make $2500 each month? How much does the woman earn each month?a) $950b)

$1500c) $1028d) $1200e) none of the above
Physics
1 answer:
Sergeeva-Olga [200]1 year ago
6 0

Answer:b

Explanation:

Given

Woman earn 50% more than her husband

Total sum of their money is =\$ 2500

Suppose man earns \$ P

so women earns P+0.5 P=P(1+0.5)=1.5 P

Sum of their money is

P+1.5 P=2500

P=\$ 1000

Women earns =1.5\times 1000=\$ 1500          

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A bullet is fired horizontally, and at the same instant a second bullet is dropped from the same height. Ignore air resistance.
Brut [27]

Answer:

They hit at the same time

Explanation:

The bullet that is fired horizontally, the horizontal component of the speed is the speed with which is its is fired and the vertical component of the speed comes in picture due to gravity only.

When the bullet is dropped from the same height, the horizontal component is zero but the vertical component arises from the gravity.

The vertical components of the velocity of both the bullets are same and thus, they fall at the same time.

<u>Answer: They hit at the same time</u>

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2 years ago
What is the amount of displacement of a runner who runs exactly 2 laps around a 400 meter track?
Alex787 [66]
Displacement is the distance and direction from the start point to the end point. Our runner finished exactly where he started. His displacement is zero.
5 0
1 year ago
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A cat is sleeping on the floor in the middle of a 3.0-m-wide room when a barking dog enters with a speed of 1.50 m/s. as the dog
kondor19780726 [428]
Good morning.


Lets make the movement function for the dog and cat.

The cat has a start position of1.5 m(the middle of the room), with an initial speed of 0 and acceleration of 0.85 m/s².

The dog has a start position of 0, an initial speed of 1.5 m/s and acceleration of -0.1 m/s².


<u>Cat:</u>

\mathsf{X = X_0+V_0t + \dfrac{at^2}{2}}\\ \\ \mathsf{X = 1.5 + \dfrac{0.85t^2}{2}}\\ \\ \\ \mathsf{X_c = 1.5 + 0.425t^2}

<u>Dog:</u>

\mathsf{X_d= 1.5t - 0.05t^2}


Let's see if the dog reach the cat. Physically, it means \mathsf{X_d = X_c}

\mathsf{1.5t - 0.05t^2 = 1.5 + 0.425t^2}\\ \\ \mathsf{0.425t^2 + 0.05t^2 - 1.5t + 1.5 = 0}\\ \\ \mathsf{0.475t^2 - 1.5t + 1.5=0}

Now we solve for <em>t</em>:

\mathsf{\Delta = (-1.5)^2 - 4\cdot0.475\cdot1.5}\\ \\ \mathsf{\Delta = 2.25-2.85=-0.6 \ \textless \  0}

We have a negative Delta. Therefore, there is no instant t when the dog reaches the cat.
6 0
2 years ago
From Kepler's third law, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to:
bazaltina [42]

Answer:

The correct option is (B).

Explanation:

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T^2\propto a^3\\\\T^2=ka^3

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(8)^2=ka^3\\\\64=ka^3\\\\a=(64)^{\dfrac{1}{3}}\\\\a=4\ AU

So, an asteroid with an orbital period of 8 years lies at an average distance from the Sun equal to 4 astronomical units.

7 0
1 year ago
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Masja [62]

Answer:

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t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

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The acceleration is 1.10261 times g

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The speed of the dragster is 416.17506 mph

5 0
2 years ago
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