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MrRissso [65]
1 year ago
5

A glider moving with a speed of 200 kilometers/hour experiences a cross wind of 30 kilometers/hour. What is the resultant speed

of the glider relative to the ground?
Physics
1 answer:
liraira [26]1 year ago
5 0
You didn't say so, but we must assume that the "200 km/hr" is
the glider's air-speed, that is, speed relative to the air. 

If the air itself is moving at 30 km/hr relative to the ground and
across the glider's direction, then the glider's speed relative to
the ground is

                 √(200² + 30²)

             =  √(40,000 + 900)

             =  √(40,900)  =  202.24... km/hr   (rounded) 
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What voltage is required to move 6A through 20?<br><br>​
Marina CMI [18]

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

7 0
1 year ago
Ancient Greek philosophers spent lots of time thinking about science and imaging explanations for the natural world. What part o
Illusion [34]

Answer:

Testing

Explanation:

Ancient Greek philosophers lived with the ideology to simply contemplate life. This means that their whole life revolved around thinking and questioning everything. This would include creative thinking, because they would sometimes come up with theories which require creativeness. They would often debate with their friends as to why their theory should be accepted or what their opinions were on the matter. More often than not, they argued a lot, and many philosophers went against some powerful people in the community and some were even sentenced to death.

The main process they didn't/couldn't do was the testing. They could never test certain theories because they did not have the means to.

4 0
1 year ago
A toy rocket engine is securely fastened to a large puck that can glide with negligible friction over a horizontal surface, take
Ad libitum [116K]

Answer:

F=(3i+3.6j)\ N

Explanation:

It is given that,

Mass of the puck, m = 4.8 kg

Initial velocity of the puck, u=(1i+0j)\ m/s

After 8 seconds, final velocity of the puck, v=(6i+6j)\ m/s

Let the x and y component of force is given by F_x\ and\ F_y.

x component of force is given by :

F_x=m\times \dfrac{v-u}{t}

F_x=4.8\times \dfrac{6-1}{8}

F_x=3\ N

y component of force is given by :

F_y=m\times \dfrac{v-u}{t}

F_y=4.8\times \dfrac{6-0}{8}

F_y=3.6\ N

So, the component of the force is F=(3i+3.6j)\ N. Hence, this is the required solution.

7 0
2 years ago
Constants Periodic Table Suppose the top surface of the vessel in the figure (Figure 1) is subjected to an external gauge pressu
Gnom [1K]

Answer:

a)  v₁ = √ [2 (P₂-P₀) /ρ + 2 (y₂ -y₁)]

b) Water does not flow,

Explanation:

a) For this exercise we will use Bernoulli's equation, where index 1 is at the exit and index 2 on the surface of the water

            P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

This case does not indicate at the surface pressure is P₂, the pressure at the outlet is P₁ = P₀, the surface velocity is zero v₂ = 0

          P₀ + ½ ρ v₁² + ρ g y₁ = P₂ + 0 + ρ g y₂

           ½ ρ v₁² = P₂-P₀ + ρ (y₂ -y₁)

          v₁² = 2 (P₂-P₀) /ρ + 2 (y₂ -y₁)

          v₁ = √ [2 (P₂-P₀) /ρ + 2 (y₂ -y₁)]

b) Reduce the pressure to SI units

         P₂ = 0.86 atm (1.01 10⁵ Pa / 1 atm) = 0.8686 10⁵ Pa

         P₀ = 1.01 10⁵ Pa

         ρ = 1 10³ kg / m³

Let's calculate

         v₁ = √ [2 (0.8686 -1.01) 10⁵/10³ + 2 (2.6)]

         v₁ = √ [-0.2828 10² + 5.2] = Ra [-23]

Water does not flow, this is because the pressure of the inner part is less than atmospheric, so that the water flows the pressure P₂> = P₀

For example if the pressure P₂ = P₀

         v₁ = √ 5.2

          v₁ = 2.28 m / s

5 0
1 year ago
50 J of work was performed in 20 seconds. How much power was used to do this task?
yuradex [85]
Power=work/time
power=50/20
50/20=2.5
Therefore A. 2.5 W
7 0
1 year ago
Read 2 more answers
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