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emmasim [6.3K]
2 years ago
14

The flight of a kicked football follows the quadratic function f(x)=−0.02x2+2.2x+2, where f(x) is the vertical distance in feet

and x is the horizontal distance the ball travels. How far, in feet, will the ball travel across the field by the time it hits the ground? Round your answer to one decimal place.
Physics
1 answer:
Margaret [11]2 years ago
7 0

Answer:

The horizontal distance the ball travels is 0.902 meters.

Explanation:

The flight of a kicked football follows the quadratic function as :

f(x)=-0.02x^2+2.2x+2

Where

f(x) is the vertical distance in feet

x is the horizontal distance the ball travels

We need to find the distance the ball travel across the field by the time it hits the ground. At this condition,

f(x) = 0

-0.02x^2+2.2x+2=0

On solving the above quadratic equation we get, the horizontal distance the ball travels as :

x = -0.902 meters

So, the horizontal distance the ball travels is 0.902 meters. Hence, this is the required solution.

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arsen [322]
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   KE = 0.5mv²

At initial conditions,

  m₁:  KE = 0.5(0.28 kg)(0.75 m/s)² = 0.07875 J

  m₂ : KE = 0.5(0.45 kg)(0 m/s)² = 0 J

Due to the momentum balance,

   m₁v₁ + m₂v₂ = (m₁ + m₂)(V)

Substituting the known values,

   (0.29 kg)(0.75 m/s) + (0.43 kg)(0 m/s) = (0.28 kg + 0.43 kg)(V)

   V = 0.2977 m/s

The kinetic energy is,
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The difference between the kinetic energies is 0.0473 J. 
7 0
2 years ago
Two identical horizontal sheets of glass have a thin film of air of thickness t between them. The glass has refractive index 1.4
Gre4nikov [31]

Answer:

the wavelength λ of the light when it is traveling in air = 560 nm

the smallest thickness t of the air film = 140 nm

Explanation:

From the question; the path difference is Δx = 2t  (since the condition of the phase difference in the maxima and minima gets interchanged)

Now for constructive interference;

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replacing ;

Δx = 2t   ; we have:

2t = (m+ \frac{1}{2} \lambda)

Given that thickness t = 700 nm

Then

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For thickness t = 980 nm that is next to constructive interference

2× 980 = (m+ \frac{1}{2} \lambda)     ----- equation (2)

Equating the difference of equation (2) and equation (1); we have:'

λ = (2 × 980) - ( 2× 700 )

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λ = 560 nm

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b)  

For the smallest thickness t_{min} ; \ \ \ m =0

∴ 2t_{min} =\frac{\lambda}{2}

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t_{min} =\frac{560}{4}

t_{min} =140 \ \  nm

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7 0
2 years ago
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Answer:

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This can be answered using the beat frequency formula, which is simply the difference between 2 frequencies.

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Answer:

Explained

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