Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
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Answer:
35 m/s down
Explanation:
The horizontal speed of the package is 70 m/s. So the time needed to reach the hikers is:
1000 m / (70 m/s) = 14.28 s
Taking down to be positive, the initial velocity needed is:
Δy = v₀ t + ½ at²
1500 m = v₀ (14.28 s) + ½ (9.8 m/s²) (14.28 s)²
v₀ = 35 m/s
The package must be launched down with an initial velocity of 35 m/s.
During the fall, the potential energy stored in the ball is converted into kinetic energy.
Thus,
PE = KE before hitting the ground
= 1/2 • mv^2
= 1/2 • 1 • 12^2
= 72J