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Inessa05 [86]
2 years ago
11

Which equation is most likely used to determine the acceleration from a velocity vs:time graph?

Physics
2 answers:
tresset_1 [31]2 years ago
7 0
Acceleration, a =  (v - u)/t

where v is the final velocity, u is the initial velocity, and t is the time.

This formula on a velocity time graph represents the slope of the graph.
 
Mars2501 [29]2 years ago
3 0

Answer: Hello there!

in this case, you have a graph of velocity vs time, then in this graph is represented the function v(t).

The acceleration is defined as the integral with respect to the time of the velocity v(t), then we could calculate the mean acceleration between two times in a next way:

a = \frac{v(t2) - v(t1))}{t2 -t1}

this is the slope between the times t2 and t1, where t2>t1 and V(t2) is the velocity at the time t2 (the final velocity) and v(t1) is the velocity at the time t1 (the initial velocity). In this case, a is the mean acceleration between these times.

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550 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to c
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Answer:

The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J

Explanation:

The given variables are

Work done = 550 J

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Thus the product of pressure and volume change = work done by gas, thus

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also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore  P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂

Also to compress the gas by a factor of 11 we have

P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11  = 909.091 J of work

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Brrunno [24]

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. Emergency rations are to be dropped from a plane to some stranded hikers. The search and rescue plane is flying at an altitude
almond37 [142]

Answer:

35 m/s down

Explanation:

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1000 m / (70 m/s) = 14.28 s

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Δy = v₀ t + ½ at²

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v₀ = 35 m/s

The package must be launched down with an initial velocity of 35 m/s.

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