A solid cylinder of mass 12.0 kg and radius 0.250 m is free to rotate without friction around its central axis. If you do 75.0 J
1 answer:
You might be interested in
Answer:
a) Impulse |J|= 219.4 kgm/s
b) Force F = 2672 N
Explanation:
Given
Height of fall h = 0.50 m
Mass M = 70 kg
Period of collision t = 0.082 s
Solution
The final velocity of the person v is zero since the person will come to rest.
The initial velocity of the person can be calculated by using the "law of conservation of energy".
Initial Kinetic energy = Final potential energy
a) Impulse
J = final momentum - initial momentum
Magnitude of impulse
b) Force
Answer:
t=0.704s
Explanation:
A child is running his 46.1 g toy car down a ramp. The ramp is 1.73 m long and forms a 40.5° angle with the flat ground. How long will it take the car to reach the bottom of the ramp if there is no friction?
from newton equation of motion , we look for the y component of the speed and look for the x component of the speed. we can then find the resultant of the speed
Vy^2=0+2*9.8*1.73sin40.5
Vy^2=22.021
Vy=4.69m/s
Vx^2=u^2+2*9.81*cos40.5
Vy^2=25.81
Vy=5.08m/s
V=(Vy^2+Vx^2)^0.5
V=47.71^0.5
V=6.9m/s
from newtons equation of motion we know that force applied is directly proportional to the rate of change in momentum on a body.
f=force applied
v=velocity final
u=initial velocity
m=mass of the toy, 0.046
f=ma
f=m(v-u)/t
v=u+at
6.9=0+9.8t
t=6.9/9.81
t=0.704s