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2 years ago

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As part of a circus performance, a man is attempting to throw a dart into an apple which is dropped from an overhead platform. U

pon release of the apple, the man has a reflex delay of 235 milliseconds before throwing the dart. If the dart is released with a speed v0 = 13 m/s, at what distance d below the platform should the man aim if the dart is to strike the apple before it hits the ground?

1 answer:

Tems11 [23]2 years ago

4 0

Answer:

The man has to aim 27.06 cm below the platform.

Explanation:

Given that,

Time = 235 millisecond

Speed = 13 m/s

We need to calculate the distance below the platform

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Where, u = initial velocity

g = acceleration due to gravity

t = time

Put the value into the formula

$s=0+\dfrac{1}{2}\times9.8\times(235\times10^{-3})^2$

$s=0.2706\ m$

$s=27.06\ cm$

Hence, The man has to aim 27.06 cm below the platform.

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Answer:

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Rewriting our equation:

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Answer:

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Explanation:

Given

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$(M.E.)_2=4.46\ J$

Decrease in Mechanical energy

$(M.E.)_1-(M.E.)_2=6.41-4.46$

$(M.E.)_1-(M.E.)_2=1.95\ J$

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