An electron is moving northward in a magnetic field. The magnetic force on the electron is toward the northeast. What is the dir
1 answer:
To solve this problem we will use the vector concept given by the cross product between two perpendicular vectors and which results in a vector perpendicular to these two. From the definition of the Magnetic Force we have to
From the property of cross product the magnetic force should point in the direction perpendicular to the plane containing the vectors v and B.
The direction of velocity is north, and the direction of the magnetic force is northeast.
This cannot be the case, as the direction of magnetic force is not perpendicular to the direction of velocity of the charge.
Therefore the correct option for the direction of the magnetic field is <em>"This situation cannot exist because of the relative orientations of the velocity and force vectors" </em>
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Answer:
The final size is approximately equal to the initial size due to a very small relative increase of in its size
Solution:
As per the question:
The energy of the proton beam, E = 250 GeV =
Distance covered by photon, d = 1 km = 1000 m
Mass of proton,
The initial size of the wave packet,
Now,
This is relativistic in nature
The rest mass energy associated with the proton is given by:
This energy of proton is
Thus the speed of the proton, v
Now, the time taken to cover 1 km = 1000 m of the distance:
T =
T =
Now, in accordance to the dispersion factor;
Thus the increase in wave packet's width is relatively quite small.
Hence, we can say that:
where
= final width
Complete Question
The complete question is shown on the first uploaded image
Answer:
The strain experienced by the specimen is 0.00116 which is option A
Explanation:
The explanation is shown on the second uploaded image
