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Alenkasestr [34]
2 years ago
10

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True B. False

Physics
2 answers:
Studentka2010 [4]2 years ago
4 0
1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

2. The maximum number of electrons allowed in a p sublevel of the 3rd principal level is? 
B.6

3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
B. All of the above.
ohaa [14]2 years ago
3 0

Answer:

1.True

2.6

3.All of the above

Explanation:

1.In a single atom,  no more than 2 electrons can occupy a single orbital.

By pauli exclusion principle, an orbital can contain a maximum of only 2 electrons, the two electrons must have opposite spins.

Therefore, it is true.

2.We know that maximum number of electrons in p sublevel is 6.

Hence, the maximum number of electrons allowed in a p sublevel of the 3rd principle level is 6.

3.A neutral atom has a ground state electronic configuration of 1s^2 2s^2.

Therefore, Total number of electrons=4

Atomic number=4

Number of protons=Atomic number=4

The atom has  total number of orbital is 2.

The element has no unpaired electrons.

Hence, all of the above is correct option.

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A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
Setler [38]

Answer

given,

mass of the ball = 3 kg

swing in vertical circle with radius = 2 m

   work done by the gravity = ?          

   work done by the tension = ?            

Work done by the gravity = - m g Δh            

 Δ h = 2 + 2 = 4 m                                                                

Work done by the gravity =- 3 \times 9.8 \times 4

                                           = -117.6 J                  

work done by gravity is equal to -117.6 J            

Work done by tension will be equal to zero.        

Zero because tension is always perpendicular to velocity

work done by tension is equal to 0 J                          

7 0
2 years ago
A glider of mass 0.240 kg is on a frictionless, horizontal track, attached to a horizontal spring of force constant 6.00 N/m. In
Sveta_85 [38]

Answer:

E_M=0.0492J.

Explanation:

The mechanical energy of the system will be the kinetic energy plus the elastic potential energy: E_M=K+U_e.

We know that the equation for the kinetic energy is K=\frac{mv^2}{2}, where <em>m </em>is the mass of the object and <em>v </em>its velocity.

We know that the equation for the elastic potential energy is U_e=\frac{k\Delta x^2}{2}, where <em>k</em> is the spring constant and \Delta x the compression (or elongation) respect to equilibrium.

So for our values we have:

E_M=K+U_e=\frac{mv^2}{2}+\frac{k \Delta x^2}{2}=\frac{(0.24kg)(0.4m/s)^2}{2}+\frac{(6N/m)(0.1m)^2}{2}=0.0492J.

6 0
1 year ago
A truck traveling at a constant speed of 40.0 km/h applies its brakes and comes to a complete stop in 5.0 s.
I am Lyosha [343]

Answer:

Part a)

v = 11.11 m/s

Part c)

a = -2.22 m/s^2

This mean the truck is decelerating and its speed is decreasing

Part e)

t = 13.89 s

Part f)

d = 77.14 m

Explanation:

Part a)

Speed of the truck is given as

v = 40 km/h

as we know that

1 km = 1000 m

1 h = 3600 s

so we will have

v =40 \times \frac{1000}{3600} m/s

v = 11.11 m/s

Part c)

Average acceleration is given as

a = \frac{v_f - v_i}{t}

now we have

a = \frac{0 - 11.11}{5}

a = -2.22 m/s^2

Part e)

as we know that it is uniform acceleration

so we can say

v_f - v_i = at

11.11 - 0 = 0.80 t

t = 13.89 s

Part f)

distance traveled by the truck is given as

d = \frac{1}{2}at^2

d = \frac{1}{2}(0.80)(13.89^2)

d = 77.14 m

4 0
1 year ago
Read 2 more answers
A small lead ball, attached to a 1.25-m rope, is being whirled in a circle that lies in the vertical plane. The ball is whirled
cluponka [151]

Explanation:

Radius of the circular path, r = 1.25 m

Angular velocity of the ball, \omega=3\ rev/s=18.84\ rad/s

It is placed 1.5 meters above the ground. Using the conservation of energy to find the height of the ball.

mgh=\dfrac{1}{2}mv^2

h=\dfrac{v^2}{2g}

Since, v=r\times \omega

h=\dfrac{(r\omega)^2}{2g}

h=\dfrac{(1.25\times 18.84)^2}{2\times 9.8}

h = 28.29 meter

So, the ball will rise to a maximum height of 1.5 m + 28.29 m = 29.796 meters. Hence, this is the required solution.

4 0
1 year ago
Tapping the surface of a pan of water generates 17.5 waves per second. If the wavelength of each wave is 45 cm, what is the spee
ElenaW [278]

Answer:

Speed of the wave is 7.87 m/s.

Explanation:

It is given that, tapping the surface of a pan of water generates 17.5 waves per second.

We know that the number of waves per second is called the frequency of a wave.

So, f = 17.5 Hz

Wavelength of each wave, \lambda=45\ cm=0.45\ m

Speed of the wave is given by :

v=f\lambda

v=17.5\times 0.45

v = 7.87 m/s

So, the speed of the wave is 7.87 m/s. Hence, this is the required solution.

5 0
1 year ago
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