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2 years ago

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True B. False

2 answers:

Studentka2010 [4]2 years ago

4 0

1. In a single atom, no more than 2 electrons can occupy a single orbital? A. True

2. The maximum number of electrons allowed in a p sublevel of the 3rd principal level is?
B.6

3. A neutral atom has a ground state electronic configuration of 1s^2 2s^2. Which of the following statements concerning this atom is/are correct?
B. All of the above.

ohaa [14]2 years ago

3 0

Answer:

1.True

2.6

3.All of the above

Explanation:

1.In a single atom, no more than 2 electrons can occupy a single orbital.

By pauli exclusion principle, an orbital can contain a maximum of only 2 electrons, the two electrons must have opposite spins.

Therefore, it is true.

2.We know that maximum number of electrons in p sublevel is 6.

Hence, the maximum number of electrons allowed in a p sublevel of the 3rd principle level is 6.

3.A neutral atom has a ground state electronic configuration of $1s^2 2s^2$ .

Therefore, Total number of electrons=4

Atomic number=4

Number of protons=Atomic number=4

The atom has total number of orbital is 2.

The element has no unpaired electrons.

Hence, all of the above is correct option.

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You are working on a laboratory device that includes a small sphere with a large electric charge Q. Because of this charged sphe

madam [21]

Answer:

the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow.

Explanation:

We can answer this exercise using Gauss's law

Ф = ∫ e . dA = $q_{int}$ / ε₀

field flow is directly proportionate to the charge found inside it, therefore if we place a Gaussian surface outside the plastic spherical shell. the flow must be zero since the charge of the sphere is equal induced in the shell, for which the net charge is zero. we see with this analysis that this shell meets the requirement to block the elective field

From the same Gaussian law it follows that if the sphere is not in the center, the only effect it has is to create more induced charge at the closest points, but the net face remains zero, so it has no effect on the flow , so no matter where the sphere is, the total induced charge is always equal to the charge on the sphere.

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2 years ago

According to Newton’s law of universal gravitation, which statements are true?

Arte-miy333 [17]

Answer: The statement first and the fourth statement are true.

Explanation:

According to Newton's gravitational law, every particle in the universe attracts every other particle with the force of attraction between the masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

As we move to higher altitude, the force of gravity on use decreases because the force of gravity is inversely proportional to the distance.

If the masses of the two objects are more then there will be greater force of gravity between them.

Therefore, the statement first and the fourth statement are true.

7 0

2 years ago

Read 2 more answers

An uncharged 30.0-µF capacitor is connected in series with a 25.0-Ω resistor, a DC battery, and an open switch. The battery has

kolezko [41]

Answer:

(a) Maximum current through resistor is 1.43 A

(b) Maximum charge capacitor receives is $1.50\times 10^{-3}\text{ C}$ .

Explanation:

(a)

In an RC (resistor-capacitor) DC circuit, when charging, the current at any time, t, is given by

$I(t) = I_0e^{-t/\tau}$

Here, $I_0$ is the maximum current and τ represents time constant which is given by RC (the product of the resistance and capacitance).

The maximum current is given by

$I = \dfrac{V}{R_\text{eff}}$

V is the emf of the battery and $R_\text{eff}$ is the effective resistance.

In this question, $R_\text{eff}$ = 10.0 Ω + 25.0 Ω = 35.0 Ω

$I = \dfrac{50.0\text{ V}}{35.0\ \Omega} = 1.43\text{ A}$

(b) The maximum charge is given

Q = CV

where C is the capacitance of the capacitor

$Q = (30.0\times10^{-6}\text{ F})(50.0\text{ V}) = 1.50\times 10^{-3}\text{ C}$

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2 years ago

Read 2 more answers

A person travels distance πR along the circumference

lakkis [162]

Answer: 2R

Explanation:

Here the person travels пR distance. We know that the circumference of a circle is 2πR. So your imaginated person has traveled the distance which is half of the circumference of the circle. And this distance is equal to its diameter. We know that diameter of a circle is two times larger than the radius. So the person's displacement is two times of the radius, means 2R. [Here 'R' means the radius of the circle]

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2 years ago

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The grooved pulley of mass m is acted on by a constant force F through a cable which is wrapped securely around the exterior of

Sidana [21]

Answer:

Answer; v= 1.2654m/s

T= 110.76N

Explanation:

Apply Momentum Principle

Fdtro - Mgridt = Iow +Mvr

Fdtro - Mgridt = mK2 v/r1 + Mvr1

85 x 3x 0.345 -11 x 9.81 x 0.23 x 3 =30 x 0.25 x 0.25 x v/0.23 + 11 x v x 0.23 =

v = 1.2654m/s

To find the timed average value

Tdt -Mgdt =MV

T x 3 - 11 x 9.81 x 3 = 11 x 0.778

T= 110.76N

3 0

2 years ago