Answer:
Explanation:
Given

Em wave is in the form of

where 


Wave constant for EM wave k is

Wavelength of wave 


Answer:
The banking angle of the road is 16.38 degrees.
Explanation:
Given:
Radius of the roadway on curve, R = 50 m
velocity of the moving car, V = 12 m/s
The banking angle can be calculated by using the formula below:
If there's no frictional force, then net force is equal to centripetal force.
MgTanΦ = (MV^2)/ R
TanΦ = V^2 / gR
Where;
Φ is the banking angle
g is acceleration due to gravity
TanΦ = (12 x 12) / (9.8 x 50)
TanΦ = 0.2939
Φ = arctan (0.2939)
Φ = 16.38 degrees
Therefore, the banking angle of the road is 16.38 degrees.
We know that:
F = ma,
so
F/a = constant
F₁/a₁ = F₂/a₂
F₂ = F₁ x 5.6 / 1
F₂ = 5.6F₁
If F₁ = 45 N,
F₂ = 5.6 x 45
= 252 N
Answer:
P =105.44 W
Explanation:
Given that
D= 10 cm ,L= 60 cm
d= 0.1 cm ,B= 6.4 mT
ρ= 1.7 x 10⁻⁸ Ω · m
The number of turns N
N= L/d
N= 60/0.1 = 600 turns
Length of wire
Lc= πDN
Lc= 3.14 x 0.1 x 600
Lc=188.4 m
The magnetic filed given as


Now by putting the values

I=5.09 A
The resistance R given as




R=4.07 Ω
Power P
p =I²R
P= 5.09² x 4.07 W
P =105.44 W