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steposvetlana [31]
2 years ago
9

Ba-11 when passing through a lock, which light means "approach the lock under full control?"

Physics
2 answers:
s344n2d4d5 [400]2 years ago
6 0

Answer

correct answer is Amber light

amber light signifies under full control

an amber light is an golden shaded traffic light demonstrating that vehicles should stop except if it is perilous to do as such, around proportional to the yellow light in the US. (US, dated) A yellow light.

gladu [14]2 years ago
3 0
Amber light is the answer, it signifies under full control
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tatiyna

Answer:

Explanation:

Given

B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)

Em wave is in the form of

B=B_0\sin (kx-\omega t)

where \omega =frequency\ of\ oscillation

k=wave\ constant

B_0=Maximum\ value\ of\ Magnetic\ Field

Wave constant for EM wave k is

k=1.05\times 10^7 m^{-1}

Wavelength of wave \lambda =\frac{2\pi }{k}

\lambda =\frac{2\pi }{1.05\times 10^7}

\lambda =5.98\times 10^{-7} m

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2 years ago
The temperature of a heat engine is 500k some of the heat generated by the engine flows to the surroundings which are at a temp
Ierofanga [76]

1-125/500)x100=efficiency

1-1/4)x100 =75pc

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1 year ago
At what angle should the roadway on a curve with a 50m radius be banked to allow cars to negotiate the curve at 12 m/s even if t
just olya [345]

Answer:

The banking angle of the road is 16.38 degrees.

Explanation:

Given:

Radius of the roadway on curve, R = 50 m

velocity of the moving car, V = 12 m/s

The banking angle can be calculated by using the formula below:

If there's no frictional force, then net force is equal to centripetal force.

MgTanΦ = (MV^2)/ R

TanΦ = V^2 / gR

Where;

Φ is the banking angle

g is acceleration due to gravity

TanΦ = (12 x 12) / (9.8 x 50)

TanΦ = 0.2939

Φ = arctan (0.2939)

Φ = 16.38 degrees

Therefore, the banking angle of the road is 16.38 degrees.

3 0
2 years ago
A boy can accelerate at 1.00 m/s 2 over a short distance. If the were to take an energy pill and suddenly have the ability to ac
VikaD [51]
We know that:
F = ma,
so
F/a = constant
F₁/a₁ = F₂/a₂
F₂ = F₁ x 5.6 / 1
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4 0
2 years ago
A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of
Leni [432]

Answer:

P =105.44 W

Explanation:

Given that

D= 10 cm ,L= 60 cm

d= 0.1 cm ,B= 6.4 mT

ρ= 1.7 x 10⁻⁸ Ω · m

The number of turns N

N= L/d

N= 60/0.1 = 600 turns

Length of wire

Lc= πDN

Lc= 3.14 x 0.1 x 600

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The magnetic filed given as

B=\dfrac{\mu_oNI}{L}

I=\dfrac{BL}{\mu_oN}

Now by putting the values

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The resistance R given as

R=\dfrac{\rho L_c}{A}

A=\dfrac{\pi}{4}\times d^2

A=\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2

R=\dfrac{1.7\times 10^{-8} \times 188.4}{\dfrac{\pi}{4}\times (0.1\times 10^{-2})^2}

R=4.07 Ω

Power P

p =I²R

P= 5.09² x 4.07 W

P =105.44 W

5 0
2 years ago
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