<span>You are given an applied force of 110 n with an angle of 30</span>°<span> with the ground. Since the force is not perpendicular or parallel to the sled then you will have two components. These components are in sine and cosine form.
for parallel component
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26
for the perpendicular component
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Momentum is conserved.
p = m₁v₁ + m₂v₂ = constant
Momentum before the collision(kick):
p = 80 * 0 + 4 * 0 = 0
Momentum after the collision:
p = 80 * v₁ + 4 * 15 = 0
Solve for v₁.
Answer:
f3 = 102 Hz
Explanation:
To find the frequency of the sound produced by the pipe you use the following formula:
n: number of the harmonic = 3
vs: speed of sound = 340 m/s
L: length of the pipe = 2.5 m
You replace the values of n, L and vs in order to calculate the frequency:
hence, the frequency of the third overtone is 102 Hz
Answer:
B. there would be a global rise in temperatures
Hence, global warming
Explanation:
hope this helped! :D
Answer: 80m
Explanation:
Distance of balloon to the ground is 3150m
Let the distance of Menin's pocket to the ground be x
Let the distance between Menin's pocket to the balloon be y
Hence, x=3150-y------1
Using the equation of motion,
V^2= U^s + 2gs--------2
U= initial speed is 0m/s
g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s
40m/s is contant since U (the coin is at rest is 0) hence V =40m/s
Slotting our values into equation 2
40^2= 0^2 + 2 * 10* (3150-y)
1600 = 0 + 63000 - 20y
1600 - 63000 = - 20y
-61400 = - 20y minus cancel out minus on both sides of the equation
61400 = 20y
Hence y = 61400/20
3070m
Hence, recall equation 1
x = 3150 - 3070
80m
I hope this solve the problem.
