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Alekssandra [29.7K]
2 years ago
7

Uranus has an orbital period of 84.07 years. In two or more complete sentences, explain how to calculate the average distance fr

om Uranus to the sun and then calculate it.
The formula is p^2=a^3
Physics
2 answers:
notka56 [123]2 years ago
7 0
<span>The Average Distance from Uranus to the Sun is 27.506. One way to solve this is by doing the oppsite of how you find the orbitial period. The way you find the orbitial period is by raising the distance to the 3rd. So what i did was take the square root of the orbitial period which is 9.16 and multiplied it by 3 to get 27.506. 

</span>
Andre45 [30]2 years ago
7 0

Answer:

Average distance from Uranus to the sun, a = 2.88 billion km

Explanation:

It is given that,

Orbital period of Uranus, T = 84.07 years = 2.65 × 10⁹ s

We have to find the average distance from Uranus to the sun. It can be calculated using Kepler's third law as :

T^2\propto a^3

or T^2=\dfrac{4\pi^2}{GM}a^3

Where

T is orbital period

a is the average distance from Uranus to the sun

G is universal gravitational constant

M is mass of sun, m=1.98\times 10^{30}\ kg

a^3=\dfrac{T^2GM}{4\pi^2}

a^3=\dfrac{(2.65\times 10^9)^2\times 6.67\times 10^{-11}\times 1.98\times 10^{30}}{4\pi^2}

a^3=2.34\times 10^{37}\ m

a=2.86\times 10^{12}\ m

a = 2.88 billion km

Hence, this is the required solution.

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The diagram is attached

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A swimmer does 3,560 J of work in 55 s. What is the swimmer’s power output? Round your answer to two significant figures. The po
Natasha2012 [34]
The value of the swimmer's power output is calculated by dividing the work done by the time it took for the work to be completed. From the given in this item,
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Rounding off to two significant figures will give us 65 W. 
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Tammy leaves the office, drives 26 km due
fredd [130]

Answer:

72.98 km

Explanation:

Her displacement is simply the distance from her final position to her initial position.

Now, I've drawn and attached a triangle diagram to depict this her movement.

Point O is her initial starting point.

Point A is the first point she gets to after travelling north while point B is the final point after travelling north east.

From the triangle, the displacement will be the distance OB which is denoted by x and can be solved from cosine rule.

Thus;

x² = 62² + 26² - 2(62 × 26)cos 120

x² = 4520 + 806

x² = 5326

x = √5326

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4 0
2 years ago
Cassy shoots a large marble (Marble A, mass: 0.06 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marbl
Lostsunrise [7]
Conservation of linear momentum:

m*v inital = m*v final

0.06*0.7 + 0.03*0 = 0.06*(-0.2) + 0.03*v

(my algebra, or use ur calculator: 0.06*.07=0.042, etc ... or ur teacher may think you got some help)

0.06*(0.7+0.2)=0.03*v, v = 0.06*0.9/0.03=1.8 m/s

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The initial velocity of a 4.0-kg box is 11 m/s, due west. After the box slides 4.0 m horizontally, its speed is 1.5 m/s. Determi
ankoles [38]

Answer:

F = - 59.375 N

Explanation:

GIVEN DATA:

Initial velocity = 11 m/s

final velocity = 1.5 m/s

let force be F

work done =  mass* F = 4*F

we know that

Change in kinetic energy = work done

kinetic energy = = \frac{1}{2}*m*(v_{2}^{2}-v_{1}^{2})

kinetic energy = = \frac{1}{2}*4*(1.5^{2}-11^{2}) = -237.5 kg m/s2

-237.5 = 4*F

F = - 59.375 N

7 0
2 years ago
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