Assumption both thunder and misty are pulling in same direction,
Net force= 1000N+800N-75N=1725N
Mass of wagon = 1725N/1.3ms^-2 = 1327kg
Answer:
Maximum emf = 5.32 V
Explanation:
Given that,
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions per second
Magnetic field, B = 0.5 T
We need to find maximum emf generated in the loop. It is based on the concept of Faraday's law. The induced emf is given by :
For maximum emf, 
So,
So, the maximum emf generated in the loop is 5.32 V.
VO2 max is considered to be the most valid measure<span> of </span>cardio respiratory fitness<span>. It </span>measures<span> the capacity of the heart, lungs, and blood to transport oxygen to the working muscles, and </span>measures<span> the utilization of oxygen by the muscles during exercise.</span>
<span>Answer: 1600 J
Explanation:
1) Data:
a) ideal gas: ⇒ pV = nRT and work = ∫ pdV
b) slowly compressed ⇒ constant temperature and not heat exchange
c) pressure: p = 2 atm
d) intitial volume: Vi = 10 liters
e) final volumen: Vf = 2 liters.
f) then the
volume of the gas is held constant ⇒ not work in this stage.
g) calculate the work done on the gas: W = ?
2) Equation
W = ∫pdV
3) Solution:
Since p = constant, W = p ∫dV = p ΔV = p (Vf - Vi)
p = 2 atm × 1.0 ×10⁵ Pa / atm = 200.000 Pa
Vi = 10 liter × 0.001 m³ ./ liter = 0.01 m³
Vf = 2 liter × 0.001 m³ / liter = 0.002 m³
W = 200.000 Pa × (0.002 m³ - 0.01m³) = - 1.600 J.
The negative sign means the work is done over the system.
That is all the work in the system because at the second stage the volume is held constant.
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Answer:
<em> The distance required = 16.97 cm</em>
Explanation:
Hook's Law
From Hook's law, the potential energy stored in a stretched spring
E = 1/2ke² ......................... Equation 1
making e the subject of the equation,
e = √(2E/k)........................ Equation 2
Where E = potential Energy of the stretched spring, k = elastic constant of the spring, e = extension.
Given: k = 450 N/m, e = 12 cm = 0.12 m.
E = 1/2(450)(0.12)²
E = 225(0.12)²
E = 3.24 J.
When the potential energy is doubled,
I.e E = 2×3.24
E = 6.48 J.
Substituting into equation 2,
e = √(2×6.48/450)
e = √0.0288
e = 0.1697 m
<em>e = 16.97 cm</em>
<em>Thus the distance required = 16.97 cm</em>
