Answer: It would increase.
Explanation:
The equation for determining the force of the gravitational pull between any two objects is:

Where G is the universal gravitational constant, m1 is the mass of one body, m2 is the mass of the other body, and r^2 is the distance between the two objects' centers squared.
Assuming the Earth's mass but not its diameter increased, in the equation above m1 (the term usually indicative of the object of larger mass) would increase, while the r^2 would not.
Thus, it goes without saying that, with some simple reasoning about fractions, an increasing numerator over a constant denominator would result in a larger number to multiply by G, thus also meaning a larger gravitational strength between Earth and whatever other object is of interest.
Answer:
Explanation:


= 250 moles.
N = n×6.02×
= 1.505×
Total charge = (1.505×
) × (1.6×
)
= 2.4×
C.
Answer:
Part a) When collision is perfectly inelastic

Part b) When collision is perfectly elastic

Explanation:
Part a)
As we know that collision is perfectly inelastic
so here we will have

so we have

now we know that in order to complete the circle we will have


now we have

Part b)
Now we know that collision is perfectly elastic
so we will have

now we have


Answer:
7.9 
Explanation:
Take the fact that mass is inversely proportional to accelertation:
m ∝ a
Therefore m = a, but because we are finding the change in acceleration, we would set our problem up to look more like this:

Using algebra, we can rearrange our equation to find the final acceleration,
:

Before plugging everything in, since you are being asked to find acceleration, you will want to convert 0.85g to m/s^2. To do this, multiply by g, which is equal to 9.8 m/s^2:
0.85g * 9.8
= 8.33
Plug everything in:
7.9
= 
(1590kg the initial weight plus the weight of the added passenger)