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Fed [463]
2 years ago
15

Einstein and Lorentz, being avid tennis players, play a fast-paced game on a court where they stand 20.0 m from each other. Bein

g very skilled players, they play without a net. The tennis ball has mass 0.0580 kg. You can ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. Unless otherwise specified, all measurements are made by the two men.
(a) Lorentz serves the ball at 80.0 m/s. What is the ball's kinetic energy?
(b) Einstein slams a return at 1.80 x 10^8 m/s. What is the ball's kinetic energy?
Physics
1 answer:
kobusy [5.1K]2 years ago
4 0

Answer:

Explanation:

a ) Kinetic energy of ball = 1/2 m v² , m is mass of the ball and v is its velocity

= 1/2 x .058 x 80²

= 185.6 J .

b ) The velocity of ball is very high so we shall find out the relativistic kinetic energy , the formula is given below

kinetic energy = mc² (    \frac{1}{\sqrt{1-\frac{v^2}{c^2} } } -1  )

= mc² x \frac{1}{\sqrt{1-\frac{v^2}{c^2} } }   - mc²

= .058 x 9 x 10¹⁶ x \frac{1}{\sqrt{1-\frac{1.8^2}{3^2} } }  - .058 x 9 x 10¹⁶

= .058 x 9 x 10¹⁶ x 1 / .8 - .058 x 9 x 10¹⁶

.058 x 9 x 10¹⁶ ( 1.25 - 1 )

= .058 x 9 x 10¹⁶ x .25

= .1305 x 10¹⁶

= 13.05 x 10¹⁴ J .

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Two objects (45.0 and 21.0 kg) are connected by a massless string that passes over a massless, frictionless pulley. The pulley h
Oksanka [162]

a) The acceleration of the objects is 3.56 m/s^2

b) The tension in the string is 280.8 N

Explanation:

a)

We start by writing the equations of motion for the two masses attached to the pulley.

For the heavier mass, we have:

m_1 g - T = m_1 a (1)

where

m_1 = 45.0 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

T is the tension in the string

a is the acceleration of the system (here we assumed that the heavier mass accelerates downward)

For the lighter mass, we have

T-m_2 g = m_2 a (2)

where

T is the tension in the string

m_2 = 21.0 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

a is the acceleration of the system (here we assumed that the lighter mass accelerates upward)

From (1) we get

T=m_1g - m_1 a

And substituting into (2),

(m_1 g - m_1 a)-m_2 g = m_2 a\\(m_1 -m_2)g  = (m_1+m_2)a\\a=\frac{m_1 - m_2}{m_1+m_2}g=\frac{45-21}{45+21}(9.8)=3.56 m/s^2

b)

From the previous part of the problem we got an expression for the tension in the string:

T=m_1g - m_1 a

Where we have

m_1 = 45.0 kg

g=9.8 m/s^2

a=3.56 m/s^2 is the acceleration, found in part a)

Susbtituting, we find

T=(45.0)(9.8)-(45.0)(3.56)=280.8 N

Learn more about forces and acceleration:

brainly.com/question/11411375

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4 0
1 year ago
A weather balloon is rising vertically from a launching pad on the ground. A technician standing 300 feet from the launching pad
avanturin [10]

Answer:

\dfrac{dh}{dt} =5\ ft/s

Explanation:

Let

h = height of balloon (in feet).

θ = angle made with line of sight and ground (in radians).

h = 300  tanθ

\dfrac{dh}{d\theta } = 300 sec^2\theta

now  \dfrac{dh}{dt} can be written as

\dfrac{dh}{dt} =\dfrac{dh}{d\theta }\times \dfrac{d\theta }{dt}

\dfrac{d\theta }{dt} = \dfrac{1}{120}\at \ \theta =\dfrac{\pi}{4}

When θ = π/4,

\dfrac{dh}{d\theta } = 300 sec^2\theta

\dfrac{dh}{d\theta } = 600

\dfrac{dh}{dt} =\dfrac{dh}{d\theta }\times \dfrac{d\theta }{dt}

\dfrac{dh}{dt} =600\times \dfrac{1}{120}

\dfrac{dh}{dt} =5\ ft/s

5 0
2 years ago
The primary additive colors are red, green, and blue, which means that any color can be constructed from a linear superposition
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The primary additive colors are red, green, and blue, which means that any color can be constructed from a linear superposition of these colors. According to this RGB (Red, Green, Blue) refers to the system for representing colors on a computer display.  It is not possible <span>that someone could have a color photograph that cannot be represented using full 24-bit color. Every color photograph can be represented using the RGB.</span>
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2 years ago
An apple is whirled round in a horizontal circle on the end of a string which is tied to the stalk. It is whirled faster and fas
Brrunno [24]

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

T=mv²/r

where T = tension force in the string , m = mass of the apple

v = speed of apple , r = radius of circle.

clearly , tension force depends on the square of the speed. hence greater the speed, greater will be the tension force.

at some point , the speed becomes large enough that it makes the tension force in the string becomes greater than the tensile strength of the string. at that point , the string breaks

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2 years ago
A lump of steel of mass 10kg at 627 degree Celsius is dropped in 100kg oil at 30 degree Celsius . the specific heat of steel And
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Answer:

700J

Explanation:

8 0
1 year ago
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