a horse gallops a distance of 60 meters in 15 seconds. then, he stops to eat some grass for 20 seconds. next, he trots for 25 se
conds over 60 meters. (the horse trots in the same direction he galloped.) finally, the horse races home (back to its starting position), traveling 120 meters in 20 seconds. graph the horse’s movements on the following distance-time chart.
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So we will first find the electrostatic potential at the center of the square
So here it is given as
here
r = distance of corner of the square from it center
now the net potential is given as
now potential energy of alpha particle at this position
Now at the mid point of one of the side
Electrostatic potential is given as
here we know that
now potential is given as
now final potential energy is given as
Now work done in this process is given as
Answer: The spring of the spring is 25 N/m.
Explanation:
Mass of the body = 25 g= 0.025 kg (1 kg = 1000 g)
Oscillation is 4 sec = 20
Oscillation in 1 sec =
Frequency of the vibration of the spring =
Force constant can be calculated bu using the relation between the frequency and, mass and spring constant 'k'
The spring of the spring is 25 N/m.