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prohojiy [21]
2 years ago
11

Complete the sentence with the word "element" or "compound." O is a(n) and H2O2 is a(n) .

Physics
2 answers:
Debora [2.8K]2 years ago
9 0
O (oxygen) is an element, whereas H2O2 (hydrogen peroxide) is a compound.
jeka942 years ago
8 0
O is an element (Oxygen) and H2O2 is a compound (Hydrogen Peroxide)
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a plane travels 204 km, northeast in 15.0 minutes. It also increases elevation by 1.6 km, upward in the same amount of time. Wha
mina [271]

Answer:

230 m/s northeast, 1.8 m/s up

Explanation:

204 kilometres = 204000 metres

15.0 minutes = 900 seconds

Velocity = Distance / Time

= 204000 / 900

= 230 m/s northeast (to 2 sf.)

1.6km = 1600 metres

Velocity = 1600 / 900

= 1.8 m/s up (to 2 sf.)

7 0
1 year ago
(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind
Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
8 0
1 year ago
A ball with a mass of 0.5 kilograms is lifted to a height of 2.0 meters and dropped. It bounces back to a height of 1.8 meters.
Degger [83]
Hi, thank you for posting your question here at Brainly.

To compute for the change in potential energy, the equation would be:

delta PE =  mg*delta h
delta PE = 0.5*9.81*(2-1.8)
delta Pe = 0.98 J

The potential energy is converted to kinetic energy.
3 0
2 years ago
Read 2 more answers
Object A of mass M is moving east at speed v. It collides with object B of mass 2M that was initially at rest. The motion of the
Firlakuza [10]

Answer:

v_B=\frac{v}{3}

Explanation:

Given that:

mass of object A, m_A=M

mass of object B, m_B=2M

speed of object A, v_A=v

So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.

m_A.v+m_B\times 0=m_A\times v_A +m_B\times v_B

M\times v+0 = M\times \frac{v}{3}+2M\times v_B

2M\times v_B= \frac{2M\times v}{3}

v_B=\frac{v}{3}

3 0
2 years ago
When a mass of 25 g is attached to a certain spring, it makes 20 complete vibrations in 4.0 s. what is the spring constant of th
earnstyle [38]

Answer: The spring  of the spring is 25 N/m.

Explanation:

Mass of the body = 25 g= 0.025 kg (1 kg = 1000 g)

Oscillation is 4 sec = 20

Oscillation in 1 sec =\frac{20}{4}=5

Frequency of the vibration of the spring = 5 s^{-1}=5 Hz

Force constant can be calculated bu using the relation between the frequency and, mass and spring constant 'k'

Frequency=\frac{1}{2\pi}\times \sqrt{\frac{k}{m}}

5 s^{-1}=\frac{1}{2\times 3.14}\times \sqrt{\frac{k}{0.025 kg}}

k=24.649 N/m\approx 25 N/m

The spring  of the spring is 25 N/m.

3 0
2 years ago
Read 2 more answers
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