Answer:
(b) 10 Wb
Explanation:
Given;
angle of inclination of magnetic field, θ = 30°
initial area of the plane, A₁ = 1 m²
initial magnetic flux through the plane, Φ₁ = 5.0 Wb
Magnetic flux is given as;
Φ = BACosθ
where;
B is the strength of magnetic field
A is the area of the plane
θ is the angle of inclination
Φ₁ = BA₁Cosθ
5 = B(1 x cos30)
B = 5/(cos30)
B = 5.7735 T
Now calculate the magnetic flux through a 2.0 m² portion of the same plane
Φ₂ = BA₂Cosθ
Φ₂ = 5.7735 x 2 x cos30
Φ₂ = 10 Wb
Therefore, the magnetic flux through a 2.0 m² portion of the same plane is is 10 Wb.
Option "b"
Answer:
B_o = 1.013μT
Explanation:
To find B_o you take into account the formula for the emf:
where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.
By applying the derivative you obtain:
when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:
hence, B_o = 1.013μT
Velocity = fλ
where f is frequency in Hz, and λ is wavelength in meters.
<span>2.04 * 10⁸ m/s = 5.09 * 10¹⁴ Hz * λ </span>
<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴ Hz ) = λ </span>
<span>4.007*10⁻⁷ m = λ </span>
<span>The wavelength of the yellow light = 4.007*10⁻⁷ m<span> </span></span>
Explanation:
Force Description
1. 
It is also known as the weight of an object. It is the force that is exerted on an object due to its mass
2. 
It is force which is exerted by a push or a pull on an object. It is also known as applied force.
3. 
It is known as resistive force. It opposes the motion of an object.
4. 
It is the force which is at a right angle to the surface or perpendicular to the surface.
