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2 years ago

If the water vapor content of air remains constant, lowering air temperature causes _____.

Physics

2 answers:

Molodets [167]2 years ago

8 0

ANSWER

An increase in relative humidity

Could you mark me brainliest plz?

sasho [114]2 years ago

8 0

Answer: The correct answer is increase in relative humidity.

Explanation:

Humidity is the amount of water vapor present in the air.

The expression for the relative humidity is defined as follows:

$Relative\ Humidity = \frac{Actual water vpor pressure}{Saturation water vapor pressure}$

The warmer air contains more water vapor than the colder air. There is decrease in the relative humidity when the temperature of the air rises. There is increase in the relative humidity when the temperature of the air falls.

Therefore, the lowering in the air temperature causes increase in relative humidity If the water vapor content of air remains constant.

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An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (

Leona [35]

Answer:

Explanation:

Given

$v_x(t)=\alpha -\beta t^2$

$\alpha =4\ m/s$

$\beta =2\ m/s^3$

$v_x(t)=4-2t^2$

$v=\frac{\mathrm{d} x}{\mathrm{d} t}$

$\int dx=\int \left ( 4-2t^2\right )dt$

$x=4t-\frac{2}{3}t^3$

acceleration of object

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=-4t$

(b)For maximum positive displacement velocity must be zero at that instant

i.e. $v=0$

$4-2t^2=0$

$t=\pm \sqrt{2}$

substitute the value of t

$x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}$

$x=3.77\ m$

7 0

2 years ago

Isabella deja caer accidentalmente un bolígrafo desde su balcón mientras celebra que resolvió satisfactoriamente un problema de

jok3333 [9.3K]

Answer:

i cant read spanish lol

Explanation:

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2 years ago

A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At

GuDViN [60]

Answer:

E/4

Explanation:

The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

Where;

E is the electric field

σ is the surface charge density

ε₀ is the electric constant.

Formula to calculate σ is;

σ = Q/A

Where;

Q is the total charge of the sheet

A is the sheet's area.

We are told the elastic sheet is a square with a side length as d, thus ;

A = d²

So;

σ = Q/d²

Putting Q/d² for σ in the electric field equation to obtain;

E = Q/(2ε₀d²)

Now, we can see that E is inversely proportional to the square of d i.e.

E ∝ 1/d²

The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.

From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;

E_new = E/4

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2 years ago

For what value m of the clockwise couple will the horizontal component ax of the pin reaction at a be zero? if a couple of that

sergejj [24]

Thank you for posting your question here at brainly. Below is the answer:

sum of Mc = 0 = -Ay(4.2 + 3cos(59)) + (275)(2.1 + 3cos(59)) + M
- Ay = (M + (275*(2.1 + 3cos(59)))/(4.2 + 3cos(59)) 

sum of Ma = 0 = (-275)(2.1) - Cy(4.2 + 3cos(59)) + M 
- Cy = (M - (275*2.1))/(4.2 + 3cos(59)) 

Ay + Cy = 275 = ((M+1002.41)+(M-577.5))/(5.745) 
= (2M + 424.91)/(5.745) 

M = ((275*5.745) - 424.91)/2 
= 577.483 which rounds off to 577 

Is it maybe supposed to be Ay - Cy = 275

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2 years ago

Calculate the weight of a 4.5 kg rabbit.

solniwko [45]

The correct answer is: 13900589.

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2 years ago