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BabaBlast [244]
2 years ago
8

If the water vapor content of air remains constant, lowering air temperature causes _____.

Physics
2 answers:
Molodets [167]2 years ago
8 0

<em>ANSWER</em>

<u>An increase in relative humidity</u>

<em><u>Could you mark me brainliest plz?</u></em>

sasho [114]2 years ago
8 0

Answer: The correct answer is increase in relative humidity.

Explanation:

Humidity is the amount of water vapor present in the air.

The expression for the relative humidity is defined as follows:

Relative\ Humidity = \frac{Actual water vpor pressure}{Saturation water vapor pressure}

The warmer air contains more water vapor than the colder air.  There is decrease in the relative humidity when the temperature of the air rises. There is increase in the relative humidity when the temperature of the air falls.

Therefore, the lowering in the air temperature causes increase in relative humidity If the water vapor content of air remains constant.

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Determine the length of a copper wire that has a resistance of 0.172 ? and cross-sectional area of 7.85 × 10-5 m2. The resistivi
KonstantinChe [14]

Answer:

Length of copper wire, l = 785 meters

Explanation:

Given that,

Resistance of the copper wire, R = 0.172 ohms

Area of cross section, A=7.85\times 10^{-5}\ m^2

Resistivity of copper, \rho=1.72\times 10^{-8}\ \Omega-m

The resistance of a wire is given by :

R=\rho\dfrac{l}{A}

l=\dfrac{RA}{\rho}

l=\dfrac{0.172\ \Omega\times 7.85\times 10^{-5}\ m^2}{1.72\times 10^{-8}\ \Omega-m}

l = 785 meters

So, the length of the copper wire is 785 meters. Hence, this is the required solution.

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2 years ago
an object having a core temperature of 1700 is removed from a furnace and placed in an environment having a constant temperature
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Answer: It will be take 2.6 hours

Explanation: Please see the attachments below

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2 years ago
What is Otter's average velocity over his entire trip when it takes him 2 minutes to walk 100 meters north and another 1 minute
Leya [2.2K]

Answer:

0.50m/s

Explanation:

Average velocity is the change in displacement of a body with respect to time.

Velocity = ∆S/∆t

∆S = 100m - 70m

∆S = 30m

∆t = 2min - 1 min

∆t = 1min = 60secs

Substitute the given parameters into the formula for velocity

Velocity = 30m/60s

Velocity = 1/2 m/s

Average Velocity = 0.5m/s

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A steel rod with a length of l = 1.55 m and a cross section of A = 4.45 cm2 is held fixed at the end points of the rod. What is
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To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.

F = AY\alpha \Delta T

Where

A = Cross-sectional Area

Y = Young's modulus

\alpha= Coefficient of linear expansion for steel

\Delta T= Temperature Raise

Our values are given as,

A = 4.45cm^2

T = 37K

\alpha = 1.17*10^{-5}K^{-1}

Y = 200*10^9Gpa

Replacing we have,

F = (4.45*10^{-4})(200*10^9)(1.17*10^{-5})(37)

F = 38526.1N

Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N

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