Question

A spaceship which is 50,000 kilometers from the center of Earth has a mass of 3,000 kilograms. What is the magnitude of the force of gravity acting on the spaceship? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.) 400 newtons 478 newtons 500 newtons 1595 newtons

Answer 1

Fg=Gx(M1M2/r^2)
Fg=478N

Answer 2

Answer:

The correct option is $478N$

Explanation:

Between two objects of a certain mass exists a force call the gravitational force. This force is the ''attraction'' force between the objects.

The equation to calculate this force is :

$F_{G}=\frac{G.m_{1}.m_{2}}{d^{2}}$ (I)

Where $F_{G}$ is the gravitational force.

Where G is the gravitational constant.

$m_{1}$ and $m_{2}$ are the masses of each object.

And $d$ is the distance between the objects (In fact is the distance between the mass centroid of each object).

In order to calculate the gravitational force, we need to replace the data in the equation.

The distance $50000km$ is equal to :

$50,000km.(\frac{1000m}{1km})=50,000,000m$

Now, if we replace in the equation (I) all the data :

$F_{G}=\frac{(6.673).(10)^{-11}\frac{Nm^{2}}{kg^{2}}.3000kg.(5.98).10^{24}kg}{(50,000,000m)^{2}}=478.854N$

$F_{G}=478.854N$ ≅ 478 N

We find that the magnitude of the force of gravity acting on the spaceship is 478 N.