A wire long and with mass is positioned horizontally near the earth's surface and perpendicular to a horizontal magnetic field o
1 answer:
The question is incomplete. The complete question is :
A wire 0.6 m long and with mass m = 11 g is positioned horizontally near the earth's surface and perpendicular to a horizontal magnetic field of magnitude B = 0.4 T. What current I must flow through the wire in order that the wire accelerate neither upwards nor downwards? The magnetic field is directed into the page.
Solution :
Given :
Length of the wire, L = 0.6 m
Mass of the wire length, m = 11 g
= kg
Magnetic field , B = 0.4 T
Know we know that :
ILB = mg
or
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Answer:
Current X has a lower potential difference than Current Y.
Explanation:
The table is as follows:
Current Volts (V)
W 9.0
X 1.5
Y 3.0
Z 4.5
There are two quantities represented in the table:
1) Current: the current is the rate of flow of electric charge in a circuit. It is given by
where q is the amount of charge that passes a given point of a circuit in a time t. It is measured in Ampere (A).
2) Potential difference: the potential difference is the difference in electric potential between two points of a circuit. The potential difference is responsible for "pushing" the electrons through the circuit and producing a current. It is measured in Volts (V).
From the table, we see that
Current X has a lower potential difference (1.5 Volts) than Current Y (3.0 Volts)
So the correct choice is
Current X has a lower potential difference than Current Y.
Answer:
0.3858 Nm
Explanation:
The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction: