In order to answer this exercise you need to use the formulas
S = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The data will be given as
Vf = final velocity = ?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
And now you do the following:
100 = 1.4t + (1/2)*0.2*t^2
t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
So the answer you are looking for is 6.5 m/s
Part b is equal to F in standards of society and it’s quality of math during the 1900s
(That was a bit of Social Studies lol)
Answer:
86.4 N downward
Explanation:
Force: This can be defined as the product of mass and acceleration of a body.
The S.I unit of Force is Newton(N).
The Expression of force is given as,
F = ma ................ Equation 1
Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.
Given: m = 72 kg, a = 1.2 m/s²
Substitute into equation 1
F = 72(1.2)
F = 86.4 N down ward.
Hence the force on the parachute harness = 86.4 N downward
Answer: 49.92 m
Explanation:
In this situation the following equation will be useful:
Where:
is the final velocity of the car, when it finally stops
is the initial velocity of the car
is the constant acceleration of the car after the driver slams on the brakes
is the stopping distance
Isolating :
Answer:
The two equations below express conservation of energy and conservation of mass for water flowing from a circular hole of radius 3 centimeters at the bottom of a cylindrical tank of radius 10 centimeters. In these equations, delta m is the mass that leaves the tank in time delta t, v is the velocity of the water flowing through the hole, and h is the height of the water in the tank at time t. g is the acceleration of gravity, which you should approximate as 1000 cm/s2.
shdh
