Ask question

Ask question

All categories

Citrus2011 [14]

1 year ago

15

Astronauts often undergo special training in which they are subjected to extremely high centripetal accelerations. One device ha

s a radius of 15 m and can accelerate a person at 98 m/s2. What is the speed of the astronaut in this device?

2 answers:

qwelly [4]1 year ago

5 0

Answer: The speed of the astronaut in this device 38.34 m/s.

Explanation:

Radius of the device ,r = 15 m

Acceleration of the device = $=a_c=98m/s^2$

Velocity of the astronaut in a device ,v = ?

$a_c=\frac{v^2}{r}$

$v^2=98 m/s^2\times 15 m$

$v=38.34 m/s$

Hence,the speed of the astronaut in this device 38.34 m/s.

egoroff_w [7]1 year ago

3 0

The centripetal acceleration of an object is given by the relation,

$Ac =V^2/R$

where Ac = centripetal acceleration = $98 m/s^2$

R = radius of rotation = 15 m

V = speed of astronaut

Hence, $\frac{V^2}{15} =98$

solving this we get, V = 38.34 m/s

You might be interested in

A tuning fork is sounded above a resonating tube (one end closed), which resonates at a length of 0.20 m and again at 0.60 m. If

Nina [5.8K]

To solve this problem we will apply the concepts related to resonance. The velocity with which sound travels in any medium may be determined if the frequency and the wavelength are known. Since the pipe is closed at one end, that produces frequencies ratio 1:3:5, then

$n_1 = \frac{V}{4L_1}$

Third resonance occurs at $5n_2$

$n_2 = \frac{V}{4L_2}$

At resonance $5n_2=n_1$

$5\frac{V}{4L_2} = \frac{V}{4L_1}$

$L_2 = 5L_1$

$L_2 = 5*0.2$

$L_2 = 1m$

Therefore at 1m will the tuning fork again create a resonance condition

6 0

2 years ago

A positive charge moving up enters a magnetic field pointing out of the screen. What is the direction of the magnetic force on t

erma4kov [3.2K]

According to the right-hand thumb rule, the forefinger gives the velocity of charge, the thumb gives the magnetic force and the center finger gives the direction of magnetic field.

then, as shown in the picture, the <span>direction of the magnetic force on the charge is in the right direction.</span>

6 0

2 years ago

Read 2 more answers

Differences between Pressure and upthrust

Angelina_Jolie [31]

Answer:

Pressure is equal to the ratio of thrust to the area in contact. Upthrust is a force exerted by the fluids on an object placed in the fluid . Upthrust acts in upward direction.

4 0

2 years ago

A horizontal uniform meter stick supported at the 50-cm mark has a mass of 0.50 kg hanging from it at the 20-cm mark and a 0.30

ElenaW [278]

Answer:

70 cm

Explanation:

0.5 kg at 20 cm

0.3 kg at 60 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

$0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm$

The position of the third mass of 0.6 kg is at 20+50 = 70 cm

7 0

2 years ago

Read 2 more answers

In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to

Salsk061 [2.6K]

Explanation:

$1.2 \mathrm{N} ; 2 \mathrm{N}$

2. $200 \mathrm{N} ; 200 \mathrm{N}$

4. $2 \mathrm{N} ; 2 \mathrm{N} ; 4 \mathrm{N}$

$5.2 \mathrm{N} ; 2 \mathrm{N} ; 2 \mathrm{N}$

$6.2 \mathrm{N} ; 2 \mathrm{N} ; 3 \mathrm{N}$

$8.200 \mathrm{N} ; 200 \mathrm{N} ; 5 \mathrm{N}$

In only the above cases (i.e 1,2,4,5,6,8 ) the object possibly moves at a constant velocity of $256 \mathrm{m} / \mathrm{s}$

You should have noticed that the sets of forces applied to the object are the same asthe ones in the prevous question. Newton's 1st law (and the 2nd law, too) makes nodistinction between the state of re st and the state of moving at a constant velocity(even a high velocity).

In both cases, the net force applied to the object must equal zero.

7 0

2 years ago