What type of system would allow light and air to enter and exit?
2 answers:
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An example that illustrates the difference is the circular motion
Explanation:
Let's start by reminding the definition of the two quantities:
- Speed is a scalar quantity that tells "how fast" an object is moving, regardless of its direction of motion.
Speed can be calculate as:
where:
d is the distance travelled
t is the time taken
- Velocity is instead a vector quantity, given by:
where;
d is the displacement of the object (displacement is a a vector connecting the initial position to the final position of motion)
t is the time taken
Since it is a vector, velocity has both a magnitude and a direction, therefore it also takes into account the direction of motion of the object.
For an object in motion in a straight line, speed and velocity are the same. However, this is not always the case.
In fact, an example of motion in which the two quantities are different is the circular motion. Consider for example the object making one complete revolution along the circle. Therefore, its average speed is the ratio between the length of the perimeter (the distance) divided by the time taken:
where r is the radius of the circle.
However, the displacement of the object is zero (because the object returns to the starting point), and so the average velocity is also zero:
Learn more about speed and velocity:
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Answer:
6 s
Explanation:
given,
Sports car accelerate from 0 to 30 mph in 1.5 s
time taken to accelerate 0 to 60 mph = ?
The power of the engine is independent of velocity and neglecting friction
power =
P = constant
the kinetic energy for 60 mph larger than this of 30 mph
=
=
=
= 4
gain in kinetic energy = P x t
time = 4 x 1.5
= 6 s
Answer: Normal force, N = 141.64 Newton
Explanation:
All the forces acting on the system and described in free body diagram are:
1) gravitational pull in downward direction
2) Normal force in upward direction
3) External force of 40 N acting at an angle of 37° with the horizontal can be resolved in two rectangular components:
i) F Cos 37° along the horizontal plane in forward direction and
ii) F Sin 37° along the vertical plane in downward direction
Applying the Newton's second law, net forces in the vertical plane are:
Net force, f = N - (mg + F Sin 37°)
As there is no acceleration in the vertical plane hence, net force f = 0.
So,
N - (mg + F Sin 37°) = 0
Adding (mg + F Sin 37°) both the sides in above equation, we get
N = mg + F Sin 37°
N = 12 9.8 + 40
0.601 because (Sin 37° = 0.601)
N = 117.6 + 24.04
N = 141.64 Newton
