1. A U.S. manufacturer wants to sell computer equipment to companies in Honduras. Because the U.S. government limits trade with
1 answer:
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We must place the pivot to keep the meter stick in balance at 90 cm (10 cm from the weight) from the free end.
Answer: Option B
<u>Explanation:</u>
In initial stage, the meter stick’s mass and mass hanged in meter stick at one end are same. Refer figure 1, the mater stick’s weight acts at the stick’s mid-point.
If in case, the meter stick is to be at balanced form, then the acting torques sum would be zero. So,
Taking out ‘mg’ as common and we get
Hence, the stick should be pivoted at a distance of,
So, the stick should be pivoted at a distance of 75 cm at the free end
Now, replace mass with another mass. i.e., four times the initial mass (as given)
If in case, the meter stick is to be at balanced form, then the acting torques sum would be zero. So,
Taking out ‘mg’ as common and we get
Hence, the stick should be pivoted at a distance of,
So, the stick should be pivoted at a distance of 10 cm from the free end.
Therefore, the option B is correct 90 cm (10 cm from the weight).
Complete Question
The compete question is shown on the first uploaded question
Answer:
The speed is
Explanation:
From the question we are told that
The distance of separation is d = 4.00 m
The distance of the listener to the center between the speakers is I = 5.00 m
The change in the distance of the speaker is by
The frequency of both speakers is
Generally the distance of the listener to the first speaker is mathematically represented as
Generally the distance of the listener to second speaker at its new position is
Generally the path difference between the speakers is mathematically represented as
Here is the wavelength which is mathematically represented as
=>
=>
=>
Here n is the order of the maxima with value of n = 1 this because we are considering two adjacent waves
=>
=>
Answer:
230
Explanation:
= Rotational speed = 3600 rad/s
I = Moment of inertia = 6 kgm²
m = Mass of flywheel = 1500 kg
v = Velocity = 15 m/s
The kinetic energy of flywheel is given by
Energy used in one acceleration
Number of accelerations would be given by
So the number of complete accelerations is 230