Question

A sample of nitrogen gas exerts a pressure of 9.80 atm at 32 C. What would its temperature be (in C) when its pressure is increased to 11.2 atm?

Answer 1

Answer:

T₂ = 111.57 °C

Explanation:

Given that

Initial pressure P₁ = 9.8 atm

T₁ = 32°C  = 273 + 32 =305  K

The final pressure   P₂ = 11.2 atm

Lets take the final temperature = T₂

We know that ,the ideal gas equation  

If the volume  of the gas is constant ,then we can say that

$\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}$

$T_2=\dfrac{P_2}{P_1}\times T_1$

Now by putting the values in the above equation ,we get

$T_2=\dfrac{11.2}{9.8}\times 305\ K$

$T_2=348.57\ K$

T₂ = 384.57 - 273 °C

T₂ = 111.57 °C