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2 years ago

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During a family trip to Laura's grandmother's house, the family cast traveled a distance of of 8 miles in 24 minutes. During the

trip they stopped for two red lights. Which statement correctly describes the motion of the car? And why?
A) The Car Traveled at an acceleration of 0.83 mi/h
B) The Car Traveled at a constant acceleration of 0.83 mi/h
C) The Car Traveled at an average speed of 20 mi/h
D) The Car Traveled at an constant speed of 20 mi/h

1 answer:

Vanyuwa [196]2 years ago

4 0

The correct answer is B

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A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is reese (enr647) – HS OnRamps 04

icang [17]

Answer:

W = 0 J

Explanation:

It is given that,

Weight of the crate, W = 100 N

Distance moved by the crate, d = 1.5 m

Let W is the work done to hold the crate 1.5 m above the ground in this way. It is given by the product of force and the displacement. Its formula is given by :

$W=F\times d\times cos\theta$

Here, $\theta=90^{\circ}$ as it is lifted vertically

$W=100\ N\times 1.5\ m\ cos(90)$

W = 0

So, the work done to hold the crate is 0. Hence, this is the required solution.

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2 years ago

Read 2 more answers

Q1: A runner is jogging in a straight line at a steady vr= 6.8 km/hr. When the runner is L= 2.4 km from the finish line, a bird

serious [3.7K]

Answer:

Q1: 3.2km

Q2: 4.8K

Explanation:

Q1:

So db is the distance of bird, and dr is the distance of runner

db = 2vr and the distance of bird is going to be 2 times greater than the runner.

formulas: db = 2vr & db = 2dr

db = 2dr
L + (L - x) = 2x
2L - x = 2x
2L = 3x
x = $\frac{2}{3}$ L

Insert it in x = $\frac{2}{3}$ L

$\frac{2}{3}$ (2.4km) = 1.6km

Now we use formula db = 2dr

db = 2L - x
db = 2(2.4km) - 1.6km
<u>db = 3.2km</u>

Q2:

Formulas: Vr = L /Δt & Vb = db/Δt

Vr = L/ Δt ⇒ Δt = $\frac{L}{Vr}$
$\frac{2.4km}{6.8km/hr}$
$\frac{6}{17}hr$

(Km cancel each other)

Vb = db/Δt ⇒ db = VbΔt
13.6km/hr $(\frac{6}{17}hr )$
<u>4.8km</u>

(hr cancel each other)

Hope it helps you :)

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2 years ago

Of the following systems, which contains the most heat?

densk [106]

Answer:d

Explanation:

Given systems are state of matter and do not contain any heat instead Heat is required to change Phase or raise the temperature of the particular system.

For example 600 kg of ice at $0^{\circ}C$

Heat Required to convert it to water at $0^{\circ}C$ is

$Q=m\times L$

Where L=latent heat of Fusion $=334 J/gm$

$Q=600\times 334\times 1000$

$Q=200.4 MJ$

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2 years ago

A carbon-dioxide laser emits infrared light with a wavelength of 10.6 μm. What is the length of a tube that will oscillate in th

alex41 [277]

Answer:

The length of a tube and number of rounds are 0.848 m and $1.77\times10^{8}\ trip\ per\ second$ .

Explanation:

Given that,

Wavelength $\lambda= 10.6\mu m$

m = 160000

We need to calculate the length

Using formula of wavelength

Laser tube behave like closed pipe

$m\dfrac{\lambda}{2}=L$

$L=160000\times\dfrac{10.6\times10^{-6}}{2}$

$L=0.848\ m$

Distance traveled by pulse of light in one back and fourth trip

$d=2L$

$d=2\times0.848$

$d=1.696\ m$

We need to calculate the time

Using formula for time

$t = \dfrac{d}{c}$

$t=\dfrac{1.696}{3\times10^{8}}$

$t=5.653\times10^{-9}\ s$

We need to calculate the number of round

Using formula of number of round

$N=\dfrac{1}{t}$

$N= \dfrac{1}{5.653\times10^{-9}}$

$N=1.77\times10^{8}\ trip\ per\ second$

Hence, The length of a tube and number of rounds are 0.848 m and $1.77\times10^{8}\ trip\ per\ second$ .

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2 years ago

If low CVP precipitates a suction alarm, rapid infusion of volume can remedy the situation after dropping the P-level.

motikmotik

Answer:

d

Explanation:

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