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nikdorinn [45]
1 year ago
9

The inventor of the photographic process in which a photograph produced without a negative by exposing objects to light on light

sensitive paper, is named _____________
a. Man Ray
c. Dorothea Lange
b. Richard Avedon
d. Pablo Picasso
Physics
2 answers:
Bad White [126]1 year ago
8 0

Answer:

it's A man ray as in one of spongebob's evil villains

i think

.w.

Nikolay [14]1 year ago
7 0
<span>A. Man Ray --------------------</span>
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Given a die, would it be more likely to get a single 6 in six rolls, at least two 6s in twelve rolls, or at least one-hundred 6s
vichka [17]

Answer:

Explanation:

In first case we are interested in one time 6 in six rolls

Thus probability = number of chances required/Total chances

= 1/6

Similarly in the second case probability = 2/12 = 1/6

In the same way in last case probability = 100/600 = 1/6

The probability is the same . Thus all the cases has equal chances  

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2 years ago
A metal bar moves through a magnetic field. the induced charges on the bar are
Dmitry [639]
I would say its a positive cgarge
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2 years ago
A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force?
Talja [164]

Answer:

1.05 N

Explanation:

K = 0.7 N/m

e = 1.5 m

F = ?

from Hooke's law of elasticity

F = Ke

= 0.7×1.5

= 1.05 N

5 0
2 years ago
A stone with mass 0.80 kg is attached to one end of a string 0.90 m long. The string will break if its tension exceeds 60.0 N. T
AleksandrR [38]

Answer:

v=8.2158m/s

Explanation:

(a) Free-body diagram attached.

(b) The stone attached with the string experiences both centripetal (towards the center) and centrifugal (away from the center) forces. The tension of the string counters the centrifugal force until it breaks.

We know that,

Centrifugal force = \frac{mv^2}{r}

where,

m = mass of the stone

v = velocity of the stone

r = length of the string

To find the maximum speed attained by the stone without the string breaking, we must equate:

\frac{mv^2}{r} =60

or, v=\sqrt \frac{{r\times 60}}{m} } =\sqrt{\frac{0.90\times60}{0.80} } =8.2158m/s

5 0
1 year ago
Some drops a ball off of the top of a 125-m-tall building. In this prob-lem, you will be solving for the time it takes the ball
Nimfa-mama [501]

Answer:

t = 5.05 s

Explanation:

This is a kinetic problem.

a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m

b) in this system the equations of motion are

              y = v₀ t + ½ g t²

where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth

e)    y = 0 + ½ g t²

     t = √ (2y / g)

     t = √(2 125 / 9.8)

     t = 5.05 s

6 0
1 year ago
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