Question

A nervous squirrel gets startled and runs 5.0\,\text m5.0m5, point, 0, space, m leftward to a nearby tree. The squirrel runs for 0.50\,\text s0.50s0, point, 50, space, s with constant acceleration, and its final speed is 15.0\,\dfrac{\text m}{\text s}15.0 s m ​ 15, point, 0, space, start fraction, m, divided by, s, end fraction. What was the squirrel's initial velocity before getting startled

Answer 1

Answer:

The squirrel's initial velocity is 5 m/s.

Explanation:

It is given that,

Distance covered by the squirrel, d = 5 m

Time taken, t = 0.5 s

Final speed of the squirrel, v = 15 m/s

To find,

The squirrel's initial velocity.

Solution,

Let a is the acceleration of the squirrel. Using the first equation of motion to find it :

$a=\dfrac{v-u}{t}$

$a=\dfrac{15-u}{0.5}$..............(1)

Let u is the initial speed of the squirrel. Using again third equation of kinematics to find it :

$v^2-u^2=2ad$

Use equation (1) to put value of a

$(15)^2-u^2=2\times \dfrac{15-u}{0.5}\times 5$

$225-u^2=20(15-u)$

On solving the above quadratic equation, we get the value of u as :

u = 5 m/s

Therefore, the squirrel's initial velocity before getting started is 5 m/s.

Answer 2

Answer:

−5.0  

Explanation: