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2 years ago

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A nervous squirrel gets startled and runs 5.0\,\text m5.0m5, point, 0, space, m leftward to a nearby tree. The squirrel runs for

0.50\,\text s0.50s0, point, 50, space, s with constant acceleration, and its final speed is 15.0\,\dfrac{\text m}{\text s}15.0 s m 15, point, 0, space, start fraction, m, divided by, s, end fraction. What was the squirrel's initial velocity before getting startled

2 answers:

Phantasy [73]2 years ago

8 0

Answer:

The squirrel's initial velocity is 5 m/s.

Explanation:

It is given that,

Distance covered by the squirrel, d = 5 m

Time taken, t = 0.5 s

Final speed of the squirrel, v = 15 m/s

To find,

The squirrel's initial velocity.

Solution,

Let a is the acceleration of the squirrel. Using the first equation of motion to find it :

$a=\dfrac{v-u}{t}$

$a=\dfrac{15-u}{0.5}$ ..............(1)

Let u is the initial speed of the squirrel. Using again third equation of kinematics to find it :

$v^2-u^2=2ad$

Use equation (1) to put value of a

$(15)^2-u^2=2\times \dfrac{15-u}{0.5}\times 5$

$225-u^2=20(15-u)$

On solving the above quadratic equation, we get the value of u as :

u = 5 m/s

Therefore, the squirrel's initial velocity before getting started is 5 m/s.

mel-nik [20]2 years ago

6 0

Answer:

−5.0

Explanation:

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sammy [17]

Answer:

The frequency of the photon decreases upon scattering

Explanation:

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2 years ago

How much energy does a 50 kg rock have if it is sitting on the edge of a 15 m cliff?

noname [10]

Answer:

7350 J

Explanation:

The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

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In this problem, we have

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Substituting numbers into the formula, we find:

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2 years ago

Suppose that a freely falling object were somehow equipped with an odometer. Would the readings of distance fallen each second i

maks197457 [2]

Answer:

1 greater distances fallen in successive seconds

Explanation:

When a body falls freely it is subjected to the action of the force of gravity, which gives an acceleration of 9.8 m / s2, consequently, we are in an accelerated movement

If we use the kinematic formula we can find the position of the body

Y = Vo t + ½ to t2

Where the initial velocity is zero or constant and the acceleration is the acceleration of gravity

Y = - ½ g t2 = - ½ 9.8 t2 = -4.9 t2

Let's look for the position for successive times

t (s) Y (m)

1 -4.9

2 -19.6

3 -43.2

The sign indicates that the positive sense is up

It can be clearly seen that the distance is greatly increased every second that passes

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2 years ago

Two small diameter, 10gm dielectric balls can slide freely on a vertical channel each carry a negative charge of 1microcoulomb.

dimulka [17.4K]

Answer:

The distance of separation is $d = 0.092 \ m$

Explanation:

The mass of the each ball is $m= 10 g = 0.01 \ kg$

The negative charge on each ball is $q_1 =q_2=q = 1 \mu C = 1 *10^{-6} \ C$

Now we are told that the lower ball is restrained from moving this implies that the net force acting on it is zero

Hence the gravitational force acting on the lower ball is equivalent to the electrostatic force i.e

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here k the the coulomb's constant with a value $k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

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2 years ago

A pillow is thrown downward with an initial speed of 6 m/s.

Yuri [45]

Given :

Initial velocity, u = -6 m/s.

Time taken, t = 4 seconds.

Acceleration due to gravity, $g = -9.8\ m/s^2$ .( Here negative sign means downward direction )

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Velocity after 4 seconds.

Solution :

By equation of motion.

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