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Naddik [55]
2 years ago
15

Suppose that a freely falling object were somehow equipped with an odometer. Would the readings of distance fallen each second i

ndicate equal or different falling distances for successive seconds? 1. Greater distances fallen in successive seconds 2. All are wrong. 3. Smaller distances fallen in successive seconds 4. Equal distances fallen in successive seconds 5. Initially equal distances fallen in successive seconds, then greater distances fallen in successive seconds
Physics
1 answer:
maks197457 [2]2 years ago
3 0

Answer:

1  greater distances fallen in successive seconds

Explanation:

When a body falls freely it is subjected to the action of the force of gravity, which gives an acceleration of 9.8 m / s2, consequently, we are in an accelerated movement

If we use the kinematic formula we can find the position of the body

       Y = Vo t + ½ to t2

Where the initial velocity is zero or constant and the acceleration is the acceleration of gravity

Y = - ½ g t2 = - ½ 9.8 t2 = -4.9 t2

Let's look for the position for successive times

t (s)      Y (m)

  1          -4.9

  2         -19.6

   3        -43.2

The sign indicates that the positive sense is up

It can be clearly seen that the distance is greatly increased every second that passes

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DedPeter [7]
<span>(cp of Copper = 387J / kg times degrees C; cp of Aluminum = 899 J / kg times degrees C; cp of Water = 4186J / kg times degrees C)
</span> Use the law of conservation of energy and assuming no heat loss to the surroundings, then 
 <span>Heat given up by copper = heat absorbed by water + heat absorbed by calorimeter 
</span><span> Working formula is 
</span> <span>Q = heat = MCp(delta T) 
</span><span> where 
</span><span> M = mass of the substance 
</span><span> Cp = specific heat of the substance 
</span><span> delta T = change in temperature 
</span> Heat given up by copper = 0.10(387)(95 - T) 
<span> Heat absorbed by water = 0.20(4186)(T - 15) 
</span><span> Heat absorbed by calorimeter = 0.28(899)(T - 15) 
</span> where 
<span> T = final temperature of the system 
</span><span> Substituting appropriate values, 

</span> 0.10(387)(95 - T) = 0.20(4186)(T - 15) + 0.28(899)(T - 15) 
<span> 38.7(95 - T) = 1088.92(T - 15) 
</span><span> 3676.50 - 38.7T = 1088.92T - 16333.8 
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8 0
2 years ago
Consider the waveform expression. y (x, t) = ym sin (0.333x + 5.36 + 585t) The transverse displacement (y) of a wave is given as
Sonja [21]

Explanation:

The waveform expression is given by :

y(x,t)=y_m\ sin(0.333x+5.36+585t)...........(1)

Where

y is the position

t is the time in seconds

The general waveform equation is given by :

y(x,t)=y_m\ sin(kx+\phi+\omega t)..........(2)

Where

k=\dfrac{2\pi}{\lambda}

\omega=2\pi f

On comparing equation (1) and (2) we get :

0.333=\dfrac{2\pi}{\lambda}

\lambda=18.86\ m

585=2\pi f

f = 93.10 Hz

Time period, T=\dfrac{1}{f}

T=\dfrac{1}{0.010}

T = 0.010 s

Phase constant, \phi=5.36\ radian

Hence, this is the required solution.

8 0
2 years ago
Workers do 8000 J of work on a 2000-N crate to push it up a ramp. If the ramp is 2 m high, what is the efficiency of the ramp?
IRISSAK [1]

Answer:

50%

Explanation:

Efficiency = work out / work in

e = Fd / W

e = (2000 N) (2 m) / (8000 J)

e = 0.5

7 0
2 years ago
Read 2 more answers
A mover hoists a 50 kg box from the ground to a height of 2 m. What was the change in the box's energy
SSSSS [86.1K]

Answer:

980 J

Explanation:

The change in box's energy is equal to its change in gravitational potential energy:

\Delta U = m g \Delta h

where

m = 50 kg is the mass of the box

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta h= 2m is the change in height of the box

Substituting numbers, we find

\Delta U = (50 kg)(9.8 m/s^2)(2 m)=980 J

3 0
2 years ago
According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f
Bond [772]

Answer:

S_{s}=300 m/s

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

Explanation:

In order to use the rule of thumb to find the speed of sound in meters per second, we need to use some conversion ratios. We know there is 1 mile per every 5 seconds after the lightning is seen. We also know that there are 5280ft in 1 mile and we also know that there are 0.3048m in 1ft. This is enough information to solve this problem. We set our conversion ratios like this:

\frac{1mi}{5s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}=321.87m/s

notice how the ratios were written in such a way that the units got cancelled when calculating them. Notice that in one ratio the miles were on the numerator of the fraction while on the other they were on the denominator, which allows us to cancel them. The same happened with the feet.

The problem asks us to express the answer to one significant figure so the speed of sound rounds to 300m/s.

For the second part of the problem we need to use conversions again. This time we will write our ratios backwards and take into account that there are 1000m to 1 km, so we get:

\frac{5s}{1mi}*\frac{1mi}{5280ft}*\frac{1ft}{0.3048m}*\frac{1000m}{1km}=3.11s/km

This means that for every 3.11s there will be a distance of 1km from the place where the lightning stroke. Since this is a rule of thumb, we round to the nearest integer for the calculations to be made easily, so the rule goes like this:

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

3 0
2 years ago
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