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gladu [14]
1 year ago
8

While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c

hange the light bulb to a higher resistance, but she wanted to keep the current the same. What will Venus need to do?
Physics
1 answer:
inessss [21]1 year ago
3 0

Answer:

<em>Venus will need to use more voltage to have the same current</em>

Explanation:

<u>Ohm's Law</u>

It states that the current through a conductor is directly proportional to the voltage applied to it and inversely proportional to the resistance of the conductor. This relationship can be written as

\displaystyle I=\frac{V}{R}

Solving for V

V=IR

Venus originally connected a resistance R_1 to a voltage V_1 to get some current I

\displaystyle I=\frac{V_1}{R_1}

The voltage needed to get that current is

V_1=IR_1

If Venus changes the light bulb to another with higher resistance, say, R_2, then the current would change, unless she uses another voltage

V_2=IR_2

Since\ R_2>R_1,\ then\ V_2>V_1

Venus will need to use more voltage to have the same current

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We know that every object exerts an attraction on every other object and the heavier the object ___ the attraction.
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1 year ago
The table shows information about four students who are running around a track. Which statement is supported by the information
Vikentia [17]

Answer:

<em>Correct option: Mohammed has less kinetic energy than Autumn.</em>

Explanation:

<u>Kinetic Energy</u>

Is the energy an object has due to its motion. If the object has a mass m and travels at a speed v, then the kinetic energy K is:

\displaystyle K=\frac{1}{2}mv^2

The information about four students includes their mass and velocity as follows:

Autumn has a mass of m1=50 kg and a velocity (magnitude) of v1=4 m/s, thus their kinetic energy is:

\displaystyle K_1=\frac{1}{2}50\cdot 4^2

K_1=400\ J

Mohammed has a mass of m2=57 kg and a velocity (magnitude) of v2=3 m/s, thus their kinetic energy is:

\displaystyle K_2=\frac{1}{2}57\cdot 3^2

K_2=256.5\ J

Lexy has a mass of m3=53 kg and a velocity (magnitude) of v3=2 m/s, thus their kinetic energy is:

\displaystyle K_3=\frac{1}{2}53\cdot 2^2

K_3=106\ J

Chiang has a mass of m4=64 kg and a velocity (magnitude) of v4=5 m/s, thus their kinetic energy is:

\displaystyle K_4=\frac{1}{2}64\cdot 5^2

K_4=800\ J

Sorted from lower kinetic energy to higher:

Lexy, Mohammed, Autumn, Chiang. Thus:

Autumn has more kinetic energy than Chiang. False

Mohammed has less kinetic energy than Autumn. True

Lexy has more kinetic energy than Mohammed. False

Chiang has less kinetic energy than Lexy. False

Correct option: Mohammed has less kinetic energy than Autumn.

3 0
1 year ago
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At what height h above the ground does the projectile have a speed of 0.5v?
maw [93]

Answer:

h=\dfrac{3v^2}{8g}

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

v=u+at

v=u-gt

Initial speed of the projectile is v and final speed is 0.5 v.

0.5v=v-gt

t=\dfrac{v}{2g}

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

h=vt-\dfrac{1}{2}gt^2

h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2

h=\dfrac{3v^2}{8g}

So, the height of the projectile above the ground is \dfrac{3v^2}{8g}. Hence, this is the required solution.

6 0
1 year ago
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